It is a stable isotope of lead metal. this isotope is of nonradioactive nature. The isotope occur naturally but can also be produced by fission reaction.
It appears as gray powder. With molecular weight of 207.9g/mol.
The boiling point is 1740° while the melting point is 327.4°
It is immediately available as typical and in custom packing of different grade of food, agriculture and pharmaceuticals.
it is used for biomedical and biological labelling. It is also used to measure pb (lead) level in blood by glycogen isotope dilution technique.
As a reaction proceeds the concentration of the reactants will get lower. Since reactions occur due to collisions that are in the correct orientation and lower concentrations leads to a lower amount of collisions, lower concentrations result in lower reaction rates. I hope this helps. Let me know if anything is unclear.
Answer:
Which of the following substances are ionic?
Check all that apply.
AlCl3
MgI2
C2H5OH
NH3
Explanation:
An ionic substance is formed between a positively charged cation and a negatively charged anion.
Ionic substances are generally formed from metal and nonmetal atoms with the metal atoms forming the cations and the nonmetal atoms forming the anions.
Among the given substances,
MgI2 is an ionic substance.
Since Mg is the metal atom. It forms a cation.
I is a nonmetal atom. It forms anion.
Hence,
MgI2 is an ionic substance.
Though AlCl3 looks like an ionic substance it is a covalent compound.
This is due to the high polarizability of
ion.
The remaining two compounds do not contain any metal atoms.
So, ethanol and NH3 are not ionic compounds.
Answer:
MgI2
Answer:
d) n = 5.4 mol
Explanation:
Given data:
Number of moles of He = ?
Volume of He gas = 120 L
Temperature and pressure = standard
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × 120 L = n × 0.0821 atm.L/ mol.K × 273.15 K
120 atm.L = n × 22.43 atm.L/ mol
n = 120 atm.L / 22.43 atm.L/ mol
n = 5.4 mol