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uysha [10]
3 years ago
13

Which is one way that Dalton's atomic theory has been shown to be incorrect?

Chemistry
1 answer:
KATRIN_1 [288]3 years ago
6 0
The answer is D. His belief is was that atoms could not be split. That is what was disproved really fast ;)
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The element that appears farthest to the is written first in the chemical name of a covalent compound.
Mashcka [7]

Answer: left

Explanation: The element that appears farthest to the

✔ left

is written first in the chemical name of a covalent compound.

3 0
3 years ago
1. 2Na + 2HCl --> 2NaCl + H2
snow_tiger [21]

Answer:

                 

Explanation:

4 0
2 years ago
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Which of the following most likely happens when the volume of a gas increases?
mafiozo [28]

the pressure of the gas increases

6 0
3 years ago
a 160 milligram sample of a radioactive isotope decays to 10 kilograms in 12 years. what is the half life of this element
Shkiper50 [21]

Answer:

3 years

Explanation:

Given data:

Initial amount of sample = 160 Kg

Amount left after 12 years = 10 Kg

Half life = ?

Solution:

at time zero = 160 Kg

1st half life = 160/2 = 80 kg

2nd half life = 80/2 = 40 kg

3rd half life = 40 / 2 = 20 kg

4th half life = 20 / 2 = 10 kg

Half life:

HL = elapsed time / half life

12 years / 4 = 3 years

8 0
3 years ago
3.8 liters of sulfur vapor, S8(g), at 921.4°C and 5.87 atm is burned in excess pure oxygen gas to give sulfur dioxide gas measur
lilavasa [31]

Answer:

116.5 g of SO₂ are formed

Explanation:

The reaction is:

S₈(g) +  8O₂(g)  → 8SO₂ (g)

Let's identify the moles of sulfur vapor, by the Ideal Gases Law

We convert the 921.4°C to Absolute T° → 921.4°C + 273 = 1194.4 K

5.87 atm . 3.8L = n . 0.082 L.atm/mol.K . 1194.4K

(5.87 atm . 3.8L) / (0.082 L.atm/mol.K . 1194.4K) = n → 0.228 moles of S₈

Ratio is 1:8, 1 mol of sulfur vapor can produce 8 moles of dioxide

Then, 0.228 moles of S₈ must produce (0.228 . 8) /1 =  1.82 moles

We convert the moles to g → 1.82 moles . 64.06 g /1mol = 116.5 g

3 0
3 years ago
Read 2 more answers
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