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salantis [7]
3 years ago
12

Which of the following are strong electrolytes? Hcl hc2h3o2 nh3 kcl

Chemistry
2 answers:
Arturiano [62]3 years ago
5 0
<h3><u>Answer;</u></h3>

HCl and KCl

<h3><u>Explanation</u>;</h3>
  • Strong electrolytes are strong bases and acids.
  • HCl is a strong acid; it dissociates completely to form H+ and Cl- ions. Thus, it is a strong, rather than weak, electrolyte.
  • CH3COOH is acetic acid, a weak acid. Only some of it will dissociate (to H+ and acetate ions), thus, it will only be a weak electrolyte.
  • NH3 will react with water as a weak base: NH3 + H2O → NH4+ + OH-. It will thus also be a weak electrolyte.  
  • KCl is a soluble ionic compound, and as such, it will be a strong electrolyte.
Vedmedyk [2.9K]3 years ago
4 0

Which includes strong electrolytes are HCl and KCl.

<h2>Further Explanation </h2>

The electrolyte solution is a solution that can conduct an electric current. In an electrolyte solution, the molecules break down (dissociate) into positive and negative electrically charged particles called ions (positive ions). The positive ion produced is called a cation and the negative ion produced is called an anion. The sum of the charges of positive ions and negative ions will be the same so that the charge of the ions in the neutral solution. These ions then conduct electricity.

The electrical conductivity of electrolyte solutions depends on the type and concentration. Some electrolyte solutions can conduct electrical current well even though the concentration is small, this solution is called a strong electrolyte. While electrolyte solutions that have weak conductivity even though the concentration is high are called weak electrolytes.

Strong electrolyte solution, which is a solution where all the molecules break down into ions (fully ionized). Because of the large number of electrically conducting ions formed, the conductivity is also strong. Generally, a strong electrolyte solution is a salt solution.

Characteristics of Strong Electrolyte Solutions

  • Conducting electric current is strong or good
  • Perfectly ionized
  • The degree or degree of ionization (a) a = 1
  • If tested, strong electrolyte solutions have bright lights and many gas bubbles appear.

Example :

Salt (NaCl, KCl, CuSO4, and KNO3),

Strong acids (HCl, HI, HBr, H2SO4, and HNO3), and

Strong bases (NaOH, Ca (OH) 2, Mg (OH) 2 and KOH)

Learn more

strong electrolytes brainly.com/question/12290030

Details

Grade:  High School

Subject:  Chemistry

keywords: Electrolytes

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You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8
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Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is pK_a  =7.82

Explanation:

From the question we are told

    The volume of base is  V_B = 26.mL = 0.0260L

     The pH of solution is  pH =  7.82

      The concentration of the acid is C_A = 0.1M

From the pH we can see that the titration is between a strong base and a weak acid

 Let assume that the the volume of acid is  V_A = 18mL= 0.018L

Generally the concentration of base

                    C_B = \frac{C_AV_A}{C_B}

Substituting value  

                     C_B = \frac{0.1 * 0.01800}{0.0260}

                    C_B= 0.0692M

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

           HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}

Now before the reaction the number of mole of base is  

            No \ of \ moles[N_B]  =  C_B * V_B

Substituting value  

                    N_B = 0.01300 * 0.0692

                         = 0.0009 \ moles    

                                 

Now before the reaction the number of mole of acid is  

            No \ of \ moles  =  C_B * V_B

Substituting value  

                    N_A = 0.01800 *0.1

                         = 0.001800 \ moles

Now after the reaction the number of moles of  base is  zero  i.e has been used up

    this mathematically represented as

                         N_B ' = N_B - N_B = 0

    The  number of moles of acid is  

             N_A ' = N_A  - N_B

                   = 0.0009\ moles

The pH of this reaction can be mathematically represented as

                 pH  = pK_a + log \frac{[base]}{[acid]}

Substituting values

                  7.82 = pK_a +log \frac{0.0009}{0.0009}

                  pK_a  =7.82        

                     

             

                                 

       

           

                     

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All of the following are strong acids except
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Explanation:

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The volume of oxygen at STP required would be 252.0 mL.

<h3>Stoichiometic problem</h3>

The equation for the complete combustion of C2H2 is as below:

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The mole ratio of C2H2 to O2 is 2:5.

1 mole of a gas at STP is 22.4 L.

At STP, 100.50 mL of C2H2 will be:

                 100.50 x 1/22400 = 0.0045 mole

Equivalent mole of O2 according to the balanced equation = 5/2 x 0.0045 = 0.01125 moles

0.01125 moles of O2 at STP = 0.01125 x 22400 = 252.0 mL

Thus, 252.0 mL of O2 gas will be required at STP.

More on stoichiometric problems can be found here: brainly.com/question/14465605

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