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sasho [114]
3 years ago
13

The diameter of a hydrogen atom is approximately 1.06 ✕ 10−10 m, as defined by the diameter of the spherical electron cloud arou

nd the nucleus. The hydrogen nucleus has a diameter of approximately 2.40 ✕ 10−15 m. (a) Imagine a scale model of a hydrogen atom where its diameter is represented by the height of the Empire State Building (1454 ft to the top of its antenna). In this model, what would be the diameter of the nucleus in millimeters? mm (b) The atom is how many times larger in volume than its nucleus? Va Vn =
Chemistry
1 answer:
mylen [45]3 years ago
6 0

Answer:

a) 10.0 mm

b) 8.7 x 10¹³ times

Explanation:

Atom diameter = 1.06 x 10⁻¹⁰ m  ________________ 100%

Nucleus diameter = 2.40 x 10⁻¹⁵ m ______________   x

x = 2.26 x 10⁻³ %

The nucleus diameter is equivalent to 2.26 x 10⁻³ % of the total atom size.

a) The Empire State Building model:

1 ft = 304.8 mm

1454 ft = 443179.2 mm

443179.2 mm______ 100%

        y           ______   2.26 x 10⁻³ %

              y = 10.0 mm

In this model,  the diameter of the nucleus would be 10.0 mm.

b) Sphere volume: V =(4 · π · r³ )/3

V atom = (4 . π .( 0.53x10⁻¹⁰)³ )/3

V atom = 6.2 x 10⁻³¹ m³

V nucleus = (4 . π .( 1.2x10⁻¹⁵)³ )/3

V nucleus = 7.2 x 10⁻⁴⁵ m³

V atom / V nucleus = 6.2 x 10⁻³¹ m³ / 7.2 x 10⁻⁴⁵ m³

V atom / V nucleus = 8.7 x 10¹³

The atom is  times 8.7 x 10¹³ larger in volume than its nucleus.        

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Write Huckel's rule below and determine how many electrons are required to make an aromatic ring with n = 0, 1, and 2.
lisov135 [29]

<u>Answer:</u> The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

<u>Explanation:</u>

Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized \pi- electrons are calculated by using the equation:

\text{Number of delocalized }\pi-\text{ electrons}=4n+2

where,

n = 0 or any whole number

  • Calculating the value of electrons for n = 0

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(0)+2=2

  • Calculating the value of electrons for n = 1

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(1)+2=6

  • Calculating the value of electrons for n = 2

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(2)+2=10

Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

4 0
3 years ago
Speed of Light Math Quiz (20 points)
Goryan [66]

The wavelength of light : 4.14 x 10⁻⁵ m

<h3>Further explanation </h3>

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

The energy of the light = 4.8 x 10⁻²¹ J

The wavelength of light :

\tt E=h.\dfrac{c}{\lambda}\\\\\lambda=\dfrac{h.c}{E}\\\\\lambda=\dfrac{6.626.10^{-34}\times 3.10^8}{4.8.10^{-21}}\\\\\lambda=4.14.10^{-5}~m

4 0
2 years ago
How many molecules are in
diamong [38]

Answer:

3.6 × 10²⁴ molecules

Explanation:

Step 1: Given data

Moles of methane (n): 6.0 moles

Step 2: Calculate the number of molecules of methane in 6.0 moles of methane

In order to convert moles to molecules, we need a conversion factor. In this case, we will use Avogadro's number: there are 6.02 × 10²³ molecules of methane in 1 mole of molecules of methane.

6.0 mol × 6.02 × 10²³ molecules/1 mol = 3.6 × 10²⁴ molecules

6 0
2 years ago
The same reaction is begun with an initial concentration of 0.05 M O3 and 0.02 M NO. Under these conditions, the reaction reache
Ivahew [28]
The balanced equation of the reaction is:

O3(g) + NO (g) → O2 (g) + NO2 (g)

Then the ratios of reaction is 1 mol O3 : 1 mol NO : 1 mol O2 : 1 mol NO2

If you have initially 0.05 M of O3 and 0.02 M of NO, the reaction will end when all the NO is consumed.

The by the stoichiometry 0.02 mol of O3 will be consumed in 8 seconds.

And the rate of reaction is change in concetration divided by the time.

The change in concentration in O3 is 0.02 M

Then, the rate respect O3 is 0.02 M / 8 seconds = 0.0025 M/s
8 0
3 years ago
ascorbic acid is a diprotic acid (Ka= 8.0x10^-5 and Ka2= 1.6x10^-12). What is the pH of a 0.260 M solution of ascorbic acid
zlopas [31]

The pH of a 0.260 M solution of ascorbic acid is 0.585. Details about pH can be found below.

<h3>How to calculate pH?</h3>

The pH of a solution can be calculated using the following expression:

pH = - log {H+}

According to this question, ascorbic acid is a diprotic acid and posseses a concentration of 0.260M. The pH can be calculated as follows;

pH = - log {0.260}

pH = 0.585

Therefore, the pH of a 0.260 M solution of ascorbic acid is 0.585.

Learn more about pH at: brainly.com/question/15289741

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7 0
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