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Tems11 [23]
3 years ago
15

Find two positive numbers such that the sum of the first and twice the second is 88

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0

the 2 numbers are 8 and 40

40*2 = 80 +8 = 88

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HELP ME PLEASE, i will give brainliest
max2010maxim [7]

Based on the right angle triangle and the given parameters, cos K = 5/13

<h3>Trigonometric ratios</h3>

  • sin = opposite / hypotenuse

  • cos = adjacent / hypotenuse

  • Tan = opposite / adjacent

Given parameters:

  • Hypotenuse = 13
  • Adjacent = 5
  • Opposite = 12

Therefore,

cos K = adjacent / hypotenuse

cos K = 5/13

Learn more about right triangle:

brainly.com/question/2217700

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6 0
2 years ago
PLZ HELP!
9966 [12]

Answer:

The area of the triangle is 36 square units

Step-by-step explanation:

First you can make the graph to set up the problem. You then plot the point 3,6 (A). You then reflect this over the Y axis which would be the point -3,6 (B). Point A is then reflected over the X axis to give you 3,-6 (C). You then multiply their total lengths 12 and 6 which is 72. Then you divide 72 by 2 because it is a triangle to get 36

8 0
3 years ago
Whoever answers right gets brainliest
Softa [21]

Answer:

37

Step-by-step explanation:

Split the arrow into a rectangle and triangle. The area of the rectangle is 7x4=28. The area of the triangle is 6*3/2=9. 28+9=37

8 0
2 years ago
What is (2-2i√3)4 equivalent to?
maxonik [38]

a. (2 - 2i√3)⁴ in polar form is 256(cos(-4π/3) + isin(-4π/3)) = 256cis(-4π/3)

b. (2 - 2i√3)⁴ in rectangular form is -128 + 128√3

To answer the question, we need to know what complex numbers are

<h3>What are complex numbers?</h3>

Complex numbers are numbers of the form z = x + iy

<h3>a. Complex numbers in polar form</h3>

Complex numbers in polar form z = r(cosθ + isinθ) where

  • r = √(x² + y²) and
  • θ = tan⁻¹(y/x)

Given that z = (2 - 2i√3)⁴ =

So,

  • x = 2 and
  • y = -2√3

So, converting to polar form

r = √(x² + y²)

= √[2² + (-2√3)²]

= √[4 + 4(3)]

= √[4 + 12]

= √16

= 4

θ = tan⁻¹(y/x)

θ = tan⁻¹(-2√3/2)

θ = tan⁻¹(-√3)

θ = -π/3

So, z = r(cosθ + isinθ)

= 4(cos(-π/3) + isin(-π/3))

<h3>Powers of complex numbers</h3>

A complex number z raised to power n is zⁿ = rⁿ(cosnθ + isin(nθ)]

z⁴ = (2 - 2i√3)⁴

= r⁴(cos4θ + isin4θ)

= 4⁴(cos(4 × -π/3) + isin(4 × -π/3))

= 256(cos(-4π/3) + isin(-4π/3))

= 256cis(-4π/3)

(2 - 2i√3)⁴ in polar form is 256(cos(-4π/3) + isin(-4π/3)) = 256cis(-4π/3)

<h3>b. Complex numbers in rectangular form</h3>

The complex number z =  r(cosθ + isinθ) in rectangular form is z = x + iy where

  • x =  rcosθ and
  • y =  rsinθ

Given that z⁴ = 256(cos(-4π/3) + isin(-4π/3)) in rectangular form,

x = rcosθ

= 256(cos(-4π/3)

= 256cos(-4 × 60°)

= 256cos(-240)

= 256cos(240)

= 256 × -1/2

= -128

y =  rsinθ

= 256sin(-4π/3)

= 256sin(-4 × 60°)

= 256sin(-240)

= -256sin240

= -256 × -√3/2

= 128√3

So, z⁴ = x + iy

= -128 + 128√3

So, (2 - 2i√3)⁴ in rectangular form is -128 + 128√3

Learn more about complex numbers in polar form here:

brainly.com/question/9678010

#SPJ1

7 0
1 year ago
Help!!! ASAP!!!!! Pls!!!
Misha Larkins [42]

Answer:

first point at 100cm then the second point at 220cm

Step-by-step explanation:

put the first point at the starting time

the the second point at 220 but 20 mins after the starting time

3 0
2 years ago
Read 2 more answers
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