Answer:
μ = 0.436
Explanation:
Given:
Change in diameter, ΔD = 7 × 10⁻³ mm
Original diameter, D = 11.2 mm = 11.2 × 10⁻³ m
Applied force, P = 14100 N
Cross-section area of the specimen, A = =
Now,
elongation due to tensile force is given as:
or
on substituting the values, we get
or
where,
is the strain in the direction of force
Now,
now, the poisson ratio, μ is given as:
on substituting the values we get,
Answer:
246.38N
Explanation:
Check the complete question in the attached diagram
The normal force acting on the body on an inclined is equal to the weight of the object as shown;
Weight = Normal force = mgcosθ
m is the mass of the box = 29kg
g is the acceleration due to gravity = 9.81m/s²
θ is the angle of inclination = 30°
N = 29 * 9.81 * cos 30°
N = 284.49cos30°
N = 246.38N
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<em>Hence the magnitude of the normal force is 246.38N</em>
