1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paladinen [302]
3 years ago
7

which of these causes seasons on earth? a. tilt of earth on its axis and movement of sun over time b. movement of earth around s

un and tilt of earth on its axis c. movement of sun over time and spinning of earth on its axis d. spinning of earth on its axis and movement of earth around sun
Physics
2 answers:
Montano1993 [528]3 years ago
8 0
Hey There,

Movement of earth around sun and tilt of earth on it's axis causes seasons on earth. So, the answer is B.

Hope this helps!
Paha777 [63]3 years ago
4 0

Answer:

b. movement of earth around sun and tilt of earth on its axis

Explanation:

???

You might be interested in
Help me, this is my last question pls.
Cloud [144]

If resultant force on the body is 0 the acceleration will also be 0.​

<h3>What is acceleration?</h3>

The term "acceleration" refers to the change in velocity with time. We must also recall that force is the product of mass and acceleration. If that is so, we can write; F = ma.

Now, we are told that the force on the body is zero so making the acceleration the subject of the formula; a = 0/mand a = 0.

Hence,  if resultant force on the body is 0 the acceleration will also be 0.​

Learn more about acceleration: brainly.com/question/2437624

6 0
2 years ago
Read 2 more answers
A student places an object with a mass of m on a disk at a position r from the center of the disk. The student starts rotating t
koban [17]

Answer:

The coefficient of static friction between the object and the disk is 0.087.

Explanation:

According to the statement, the object on the disk experiments a centrifugal force due to static friction. From 2nd Newton's Law, we can represent the object by the following formula:

\Sigma F_{r} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R} (1)

\Sigma F_{y} = N - m\cdot g = 0 (2)

Where:

N - Normal force from the ground on the object, measured in newtons.

m - Mass of the object, measured in newtons.

g - Gravitational acceleration, measured in meters per square second.

v - Linear speed of rotation of the disk, measured in meters per second.

R - Distance of the object from the center of the disk, measured in meters.

By applying (2) on (1), we obtain the following formula:

\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}

\mu_{s} = \frac{v^{2}}{g\cdot R}

If we know that v = 0.8\,\frac{m}{s}, g = 9.807\,\frac{m}{s^{2}} and R = 0.75\,m, then the coefficient of static friction between the object and the disk is:

\mu_{s} = \frac{\left(0.8\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.75\,m)}

\mu_{s} = 0.087

The coefficient of static friction between the object and the disk is 0.087.

5 0
2 years ago
The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the
Eddi Din [679]

Answer:

x = D (M/M-m) 2.41

Explanation:

a) Let's apply Newton's second law to find the summation of force, where each force is given by the law of universal gravitation

        F = g m₁m₂ / r²

        Σ F = 0

       F1- F2 = 0

       F1 = F2

We set the reference system in the body of greatest mass (M) the planet

       F1 = g m₁ M / x²

       F2 = G m1 m / (D-x)²

      G m₁ M / x² = G m₁ m / (D-x)²

      M (D-x)² = m x²

      MD² -2MD x + M x² = m x²

     x² (M-m) -2MD x + MD² = 0

We solve the second degree equation

     x = [2MD  ±√ (4M²D² - 4 (M-m) MD²)] / 2 (M-m)

     x = {2MD ± 2D √ (M² + (M-m) M)} / 2 (M-m)

     x = D {M  ±  Ra (2M²-mM)} / (M-m)

    x = D (M ± M √ (2-m/M)) / (M-m)

    x = D (M / (M-m)) (1 ±√ (2-m/M)

Let's analyze this result, the value of M-m >> 1, so if we take the negative root, the value of x would be negative, it is out of the point between the two bodies, so the correct result must be taken with the positive root

 

    x = D (M / (M-m)) (1 + √2)

     x = D (M/M-m) 2.41

b) X = 2/3 D

     x = D (M/M-m) 2.41

     2/3 D = D (M/(M-m)) 2.41

     2/3 (M-m) = M 2.41

     2/3 M - 2/3 m = 2.41 M

     1.743 M = 0.667 m

     M/m = 0.667/1.743

     M/m =  0.38

3 0
2 years ago
What is the magnitude of the angular momentum relative to the origin of the 100 g particle in the figure(figure 1 ? express your
torisob [31]
<span>Radius distance from origin to particle = √ (2²+1²) = √5 m = R 
I = MR² = (0.200)(5) = 1.00 kg-m² 
Θ = arctan 2/1 = 63.4° = R's angle CCW from horizontal 
V = 3.0 m/s 
V component that is at 90° to R = 3.0(sin 90°- 63.4°) = 3.0(sin 26.6°) = 1.3433 m/s 
w = [V component / R] = 1.3433/√5 = 0.601 rad/s 
size of angular momentum of particle relative to origin = Iw = (1.00)(0.601) = 0.601 kgm²/s</span><span>


i hope I'm right</span>
6 0
3 years ago
Why is moving a box with a mass of 37 kilograms a distance of 37 meters why it did 360 joules of work in two minutes when moving
alexira [117]
Power= energy/time= 360/(2*60)=3 W thats 2nd option
6 0
3 years ago
Other questions:
  • After being struck by a bowling ball, a 1.3 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.3 kg
    14·1 answer
  • Who are a congressional representative's Constituents
    5·1 answer
  • in the hydrologic cycle, water from the ocean _____ (condenses, precipitates, transpires,or evaporates) into the atmosphere wher
    13·2 answers
  • Part 1: A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the en
    13·1 answer
  • What happens when an object with a higher density is placed in a container with a lower density liquid?
    11·1 answer
  • Two small particles of mass m1 and mass m2 attract each other with a force that varies inversely with the cube of their separati
    11·1 answer
  • Water is pouring into an inverted cone at the rate of 3.14 cubic meters per minute. The height of the cone is 10 meters and the
    10·1 answer
  • You go to the playground and slide down the slide, a 3.6-m-long ramp at an angle of 40. ∘ with respect to horizontal. The pants
    10·1 answer
  • A spring with spring constant 17.0 N/m hangs from the ceiling. A ball is suspended from the spring and allowed to come to rest.
    6·1 answer
  • A particle moving with initial velocity of 5m/s is subjected to a uniform acceleration of -2.5 m/s2.find the displacement for ne
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!