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3 years ago

Can you give me a pic or explanation of amp structure

Chemistry

2 answers:

Varvara68 [4.7K]3 years ago

6 0

Adenosine monophosphate (AMP), also known as 5'-adenylic acid, is a nucleotide. AMP consists of a phosphate group, the sugar ribose, and the nucleobase adenine; it is an ester of phosphoric acid and the nucleosideadenosine. As a substituent it takes the form of the prefix adenylyl-.

Mrrafil [7]3 years ago

4 0

There you go. I gave you a image.

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If 20.0 mL of a 0.0800 M HNO3, 35.0 mL of a 0.0800 M KSCN, and 40.0 mL of a 0.0800 M Fe(NO3)3 are combined, what is the initial

Tems11 [23]

Answer:

0.0295M

Explanation:

As you can see, in the mixture you have KSCN and other compounds. The KSCN in solution is dissolved in K⁺ ions and SCN⁻ ions. That means initial concentration of SCN⁻ ions is the same of KSCN, 0.0800M.

You are adding 35.0mL of this solution and the total volume of the mixture is 20.0mL + 35.0mL + 40.0mL = 95.0mL.

That means you are diluting your solution 95.0mL / 35.0mL = 2.714 times.

And the concentration of SCN⁻ is:

0.0800M / 2.714 =

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3 years ago

The molar ratio of HPO42- to H2PO4- in a solution is 1.4. Calculate the pH of the solution. Phosphoric acid (H3PO4) is a triprot

Bezzdna [24]

Given is the ratio of conjugate base and conjugate acid of phosphoric acid. pH of a substance is the concentration of the hydrogen ions in its solution and higher this concentration lower is the value of pH.

pKa value is a measure of the strength of acid, it is the negative log of acid dissociation constant Ka.

7 0

3 years ago

What is the net ionic equation of the reaction of MgSO4 with Pb(NO3)2?

NemiM [27]

Hey there!:

Write the molecular equation for the reaction of MgSO4 with Pb(NO3)2 :

MgSO4(aq) + Pb(NO3)2(aq) ---> Mg(NO3)2(aq) + PbSO4(s)

Write the total ionic equation for the reaction :

Mg²⁺ (aq) + SO₄⁻² (aq) + Pb²⁺ (aq) + 2 NO₃⁻¹ (aq) + PbSO₄(s)

Therefore:

Cancel the spectator ions on both sides:

Pb²⁺ (aq) + SO₄⁻² (aq) ---> PbSO4(s)

Hope that helps!

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3 years ago

The average human body temperature is 98.6 °

grin007 [14]

It's 37 degrees Celsius

3 0

3 years ago

7. Suppose 1.01 g of iron (III) chloride is placed in a 10.00-mL volumetric flask with a bit of water in it. The flask is shaken

Nana76 [90]

<u>Answer:</u> The molarity of Iron (III) chloride is 0.622 M.

<u>Explanation:</u>

Molarity is defined as the number of moles present in one liter of solution. The equation used to calculate molarity of the solution is:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of iron (III) chloride = 1.01 g

Molar mass of iron (III) chloride = 162.2 g/mol

Volume of the solution = 10 mL

Putting values in above equation, we get:

$\text{Molarity of Iron (III) chloride}=\frac{1.01g\times 1000}{162.2g/mol\times 10mL}\\\\\text{Molarity of Iron (III) chloride}=0.622M$

Hence, the molarity of Iron (III) chloride is 0.622 M.

3 0

3 years ago