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Brut [27]
3 years ago
14

Plz help bc this s due at exactly 3:30pm

Chemistry
2 answers:
Orlov [11]3 years ago
7 0

Answer:

Is it talking about the differences about them or the ways they are the same

Explanation:

ioda3 years ago
4 0
I’m pretty sure it’s d.
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The total volume of seawater is 1.5 x 1021L .Assume that seawater contains 3.1 percent sodium chloride by mass and that its dens
son4ous [18]

Answer:

Mass in kg = 4.7*10^19 kg

Mass in tons = 5.2*10^16 tons

Explanation:

<u>Given:</u>

Total volume of sea water = 1.5*10^21 L

Mass % NaCl in seawater = 3.1%

Density of seawater = 1.03 g/ml

<u>To determine:</u>

Total mass of NaCl in kg and in tons

<u>Calculation:</u>

Unit conversion:

1 L = 1000 ml

The volume of seawater in ml is:

=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml

Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g

Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24}  g=4.7*10^{22} g

To convert mass from g to Kg:

1000 g = 1 kg

Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg

To convert mass from g to tons:

1 ton = 9.072*10^6 g

Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons

5 0
3 years ago
One day on her walk home from school, Leann noticed some rust on an old car.
skad [1K]

Answer:

Iron and Oxygen

Explanation:

Fe is Iron and O2 is Oxygen

4 0
3 years ago
A balloon containing 0.0400 mol of a gas with a volume of 500 mL was expanded to 1.00 L.
ANTONII [103]

Answer:

b

Explanation:

answered it correctly

3 0
3 years ago
Read 2 more answers
In a parallel circuit, there is only one path for current to take.<br> true or false
OlgaM077 [116]
The answer is true!!!!!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
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The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C7H5N3O6 (227.1 g/mol), is soluble in benzene C6H6. How many grams of TNT
Alexeev081 [22]

Answer:

Explanation:

formula of osmotic pressure is as follows

p= n RT

n is mole of solute per unit volume

If m be the grams of solute needed

m gram = m / 227.1 moles

m / 227.1 moles dissolved in .279 litres

n = m / (227.1 x .279 )

= m / 63.36

substituting the values in the osmotic pressure formula

5.14 = (m / 63.36)  x .082 x 298

m / 63.36 = .21

m = 13.32 grams .

7 0
2 years ago
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