1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brut [27]
3 years ago
14

Plz help bc this s due at exactly 3:30pm

Chemistry
2 answers:
Orlov [11]3 years ago
7 0

Answer:

Is it talking about the differences about them or the ways they are the same

Explanation:

ioda3 years ago
4 0
I’m pretty sure it’s d.
You might be interested in
Use standard enthalpies of formation to calculate ΔH∘rxn for the following reaction______.2H2S(g)+3O2(g)→2H2O(l)+2SO2(g) ΔH∘rxn
Ahat [919]

Answer:

-1,103.39KJ/mol

Explanation:

We use the subtract the standard enthalphies of formation of the reactants from that of the products. It must be taken into consideration that the enthalpy of formation of elements and their molecules alone are not taken into consideration. Hence, what we would be considering are the standard enthalpies of formation of H2S, H2O and SO2.

In places where we have more than one mole, we multiply by the number of moles as seen in the balanced chemical equations.

The standard enthalpies of the molecules above are as follows:

H2S = -20.63KJ/mol

H2O = -285.8KJ/mol

SO2 = -296.84KJ/mol

O2 = 0KJ/mol

ΔrH⦵ = [2ΔfH⦵(H2O) + 2 ΔfH⦵(SO2)] − [ΔfH⦵(H2S) + 3

 ΔfH⦵(O2)]

ΔrH⦵ =[(2 × -285.8) + (2 × -296.84)]

-[ 3 × -20.63)]

= (-571.6 - 593.68 + 61.89) = -1,103.39KJ/mol

6 0
4 years ago
Read the reaction and the statement. H2(g) + I2(g) ⇌ 2HI(g) The concentration of H2, I2 and HI are measured as 0.04 M, 0.08 M an
hjlf

Answer:

45467777777777yt3457942

4 0
3 years ago
I need help can someone please do so?
larisa86 [58]

Answer:

0.296 J/g°C

Explanation:

Step 1:

Data obtained from the question.

Mass (M) =35g

Heat Absorbed (Q) = 1606 J

Initial temperature (T1) = 10°C

Final temperature (T2) = 165°C

Change in temperature (ΔT) = T2 – T1 = 165°C – 10°C = 155°C

Specific heat capacity (C) =..?

Step 2:

Determination of the specific heat capacity of iron.

Q = MCΔT

C = Q/MΔT

C = 1606 / (35 x 155)

C = 0.296 J/g°C

Therefore, the specific heat capacity of iron is 0.296 J/g°C

8 0
3 years ago
Which of the following have the most similar properties?
rjkz [21]

Answer:

             Option-B (Carbon and Silicon)

Explanation:

                  Among the given pairs only carbon and silicon have the most similar properties. This is because,

Sodium and Magnesium belong to different groups. Sodium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Magnesium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

                                           2 Na  +  Cl₂    →     NaCl

                                           Mg  +  Cl₂    →    MgCl₂

As shown in reactions when Sodium and Magnesium are treated with Cl₂ they give a products with different proportions.

Carbon and Silicon show almost same properties because both belong to Group IV hence both are capable of forming four bonds. Also, they share the same property of self linkage in making a long chains.

Argon and Chlorine also belong to two different groups. Argon is present in Group VIII (Noble Gases) and Chlorine is present in Group VII (Halogens). Hence, Argon is an inert specie which is non reactive while Chlorine gives different reaction easily.

Potassium and Calcium belong to different groups. Potassium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Calcium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

                                           2 K  +  Cl₂    →     KCl

                                           Ca  +  Cl₂    →    CaCl₂

As shown in reactions when Potassium and Calcium are treated with Cl₂ they give a products with different proportions.

6 0
4 years ago
How many moles of solute are in 53.1 mL of 12.5M HCI?
Deffense [45]
Molarity = moles of solute/volume of solution in liters.

From this relation, we can figure out the number of moles of solute by multiplying the molarity of the solution by the volume in liters.

We have 53.1 mL, or 0.0531 L, of a 12.5 M, or 12.5 mol/L, solution. Multiplying 12.5 mol/L by 0.0531 L, we obtain 0.664 moles. So, in this volume of solution, there are 0.664 moles of solute (HCl).
6 0
2 years ago
Other questions:
  • If you had a 5 gram sample of lawrencium how much would still remain in 30 minutes
    6·1 answer
  • An online wave simulator created these four waves. Which wave has the lowest frequency?
    10·2 answers
  • 1.73 lbs of salt in 3.70 lbs of water what is the percentage of salt in the mixture
    14·1 answer
  • The nutrition label on the back of a package of hotdogs (purchased within the US) indicates that one hotdog contains 100 calorie
    12·1 answer
  • which force will decrease if the surface of a ramp is made smoother. gravity, magnetism, friction, or electricity
    11·1 answer
  • The ground -state electron configuration contains 6p unpaired electrons .
    8·1 answer
  • Please help and thank you
    12·1 answer
  • Can someone explain to me what numbers are acidic, base, or neutral on a ph scale?
    10·1 answer
  • A student used a Vernier magnetic field sensor to measure the strength of the magnetic field generated by a bar magnet. At which
    13·1 answer
  • Migration can best enhance the survival of individuals because it
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!