Answer: have a subject and a verb
Explanation:
Answer:
Explanation:
Given data
time=0.530 h
Average velocity Vavg=19.0 km/s
To find
Displacement Δx
Solution
The Formula for average velocity is given as
Answer:
0.30581
0.24464
Explanation:
= Coefficient of static friction
= Coefficient of kinetic friction
= 75 N
= 60 N
Normal force
Frictional force
The coefficient of static friction is 0.30581
Kinetic force
The coefficient of kinetic friction is 0.24464
Answer:
a) T1 = 7.48 N
b) T2 = 18.09N
c) I = 0.0115 kgm^2
Explanation:
Mass of textbook= 2.08kg
Diameter of cord = 0.130m
Radius = 0.130/2 = 0.065m
Distance = 1.30m
Time interval = 0.830 sec
From equation of motion,
S = ut + 1/2at^2
U = initial velocity = 0
S = 1/2at^2
2S = at^2
a = 2S/t^2
a = 2(1.3) / 0.830^2
a = 3.77 m/s^2
T1 = m1*a ..........(1)
m2g - T2 = m2a..........(2)
T1 = (2.08)(3.77)
T1 = 7.84N
m2g - T2 = m2a
T2 = m2g - m2a
T2 = m2(g - a)
T2 = 3(9.80 - 3.77)
T2 = 3(6.03)
T2 = 18.09N
Moment of inertia (I)
I = [(T2 - T1) r^2]/a
I = [(18.09 - 7.84)(0.065)^2]/ 3.77
I = (10.25)(0.065)^2 / 3.77
I = 0.0115 kgm^2