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diamong [38]
3 years ago
14

Both independent and dependent clauses

Physics
2 answers:
marin [14]3 years ago
6 0

Answer:

B

Explanation:

Assoli18 [71]3 years ago
5 0

Answer: have a subject and a verb

Explanation:

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What velocity must a 1210 kg car have in order to have the same momentum as the pickup truck in the sample problem
harina [27]

Answer:

P=mv 2250*25=56250

Explanation:

p of truck =2250*25 =56250

since p of truck = p of car

then p of car = 56250

therefore p of car = 1210 * v

or, 56520=1210v

or,v= 56520/1210=46.48

so, v of car is 46.48m/s

3 0
3 years ago
What is the height of a building (in meters) if it takes a rock 8.2 seconds to drop from it's roof?
stellarik [79]

Answer:

d = 329.81m

Explanation:

V_f = V_0+a*t

V_f = Velocity final

V_0 = Velocity initial

a = acceleration

t = time

V_f = (0m/s)+(9.81m/s²)*(8.2s)

V_f = 80.442m/s

d = ((V_f-V_0)/2)*t

d = distance

d = ((80.442m/s-0m/s)/2)*(8.2s)

d = 329.81m

6 0
3 years ago
Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 18.0 cm and carries a
Helen [10]

Answer:

Explanation:

The wires are in circular shape . They have common center .

magnetic field due to circular wire is given by the formula

B = \frac{\mu_0\times I }{2r}

 where I is current , r is radius of the coil .

magnetic field due to inner wire

= \frac{\mu_0\times 10 }{2\times.09}

magnetic field due to outer wire

= \frac{\mu_0\times I }{2\times.15}

These should be equal  and opposite so that by cancelling each other , they create zero field.

\frac{\mu_0\times 10 }{2\times.09}  = \frac{\mu_0\times I }{2\times.15}

I = 16.66  A

Direction of current should be in opposite direction ie anticlockwise when looking from above.

6 0
4 years ago
A satellite is to be launched into an orbit of radius,r Show that v = 2gr, where V is the
Snezhnost [94]

Explanation:

We start by using the conservation law of energy:

\Delta{K} + \Delta{U} = 0

or

\dfrac{1}{2}mv^2 - G\dfrac{mM}{r} = 0

Simplifying the above equation, we get

v^2 = 2G\dfrac{M}{r}

We can rewrite this as

v^2 = 2\left(G\dfrac{M}{r^2}\right)r

Note that the expression inside the parenthesis is simply the acceleration due to gravity g so we can write

v^2 = 2gr

where v is the launch velocity.

6 0
3 years ago
There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.
Sloan [31]

Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes.  By plugging those values in we get:

A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g


There is 6.25 grams left of Ra-229 after 12 minutes.

4 0
4 years ago
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