Answer:
The acceleration of the ball is constant and equal to -9.81 m/s² (acting downwards)
The velocity of the ball reduces at a constant rate with time on its way up
Explanation:
The motion of the ball upwards is described by the following equation;
v = u - g × t
v² = u² - 2 × g × s
Where;
v = The final velocity of the ball
u = The initial velocity of the ball
g = The acceleration due to gravity = Constant
s = The height of the bass after a given time, t
t = The time in which the ball is rising
Therefore, the acceleration of the ball = The acceleration due to gravity (Constant) = -9.81 m/s²↓
From v = u - g × t = u - 9.81 × t , the velocity of the ball reduces at a constant rate with time on its way up.
A) 
The magnitude of the capacitive reactance is given by

where
is the angular frequency
C is the capacitance
While the magnitude of the inductive capacitance is given by

where L is the inductance.
Since we want the two reactances to be equal, we have

So we find

B) 7449 rad/s
In this case, we have
is the inductance
is the capacitance
Therefore, substituting in the formula for the angular frequency, we find

C) 
Now we can us the formulas of the reactances written in part A). We have:
- Capacitive reactance:

- Inductive reactance:

<span>as i recall, gravity is relative to the square of the distance.
so if the distance is tripled, then the gravitational attraction would be reduced by 3^2 or 1/9.
so F1 = F0/9
if the satellite is 2R from the center, and is moved to 4R (doubled would be 3R, tripled is 4R) then the distance is twice, and gravity would be 2^2 or 1/4.
</span>
Answer:
i found this on google "A universal gate is a gate which can implement any Boolean function without need to use any other gate type. The NAND and NOR gates are universal gates. In practice, this is advantageous since NAND and NOR gates are economical and easier to fabricate and are the basic gates used in all IC digital logic families.
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Explanation: