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hjlf
3 years ago
9

Hard water deposits (calcium carbonate) have built up around your bathroom sink. which of these substances would be most effecti

ve in dissolving the deposits
Chemistry
2 answers:
brilliants [131]3 years ago
7 0
The answer would be: <span> vinegar (acetic acid).

To dissolve deposit that calcified, you need to dissolve the calcium. Calcium is one of the metal that makes base pH. It will react with acid compound and produce a molecule of water. Ammonia, bleach, lye </span><span>, and baking soda are all base and won't react with the </span><span>calcium carbonate. Vinegar is acid and will react to it.

</span>
Stolb23 [73]3 years ago
6 0
Hello!

Vinegar would be most effective in dissolving the deposits of Hard Water.

Vinegar (CH₃COOH) is a weak acid, while Calcium Carbonate (CaCO₃), being the salt of a weak acid, will be a weak base. These two compounds will react together in the following way:

2CH₃COOH + CaCO₃ → (CH₃COO)₂Ca + H₂CO₃

H₂CO₃ reacts further to yield Water and CO₂

H₂CO₃ → H₂O + CO₂(g)

So, vinegar would be effective at dissolving CaCO₃, and we should see bubbles as a proof that a reaction has occurred.

Have a nice day!
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AveGali [126]

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Electronic configuration given by

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Or

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6 0
2 years ago
3.75 g of an unknown gas at 59 °C and 1.00 atm is stored in a 1.35-L flask. What is the molar mass of the gas?
MAXImum [283]
You need to find moles of the gas, so you would use the ideal gas law:
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Pressure
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R= gas constant
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4 0
3 years ago
Coal can be used to generate hydrogen gas (a potential fuel) by thefollowing endothermic reaction.C(s) + H2O (g) &lt;==&gt; CO(g
SpyIntel [72]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

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For the given equation:

C(s) + H_2O (g)\leftrightharpoons CO(g) + H_2(g)

Given that reaction is an endothermic reaction.

For the given options:

a)Adding more C

If the concentration of C that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of C takes place. Therefore, the equilibrium will shift in the right direction to wards the formation of hydrogen gas.

b) Adding more H_2O

If the concentration of water that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of water  takes place. Therefore, the equilibrium will shift in the right direction towards the formation of hydrogen gas.

c) Raising the temperature  of the reaction mixture

If the temperature is increased,heat of the equilibrium mixture will also increase so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in heat that is decrease in temperature occurs.

As, this is an endothermic reaction, forward reaction will decrease the temperature. Hence, the equilibrium will shift in the right direction that is towards the formation of hydrogen gas.  

d) Increasing the volume  of reaction mixture

If the volume of the container is increased, the pressure will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where increase in pressure is taking place. As the number of moles of gas molecules is greater at the product side. So, the equilibrium will shift in the right direction that is towards the formation of hydrogen gas.  

e) Adding a catalyst  to reaction mixture

Role of catalyst is to attain the equilibrium quickly without disturbing the state of equilibrium. Hence, addition of catalyst will not change the equilibrium of the reaction.  

f) Adding an inert gas to reaction mixture

Adding inert gas to the mixture at constant volume will not effect the equilibrium. Hence, addition of an inert gas will not change the equilibrium of the reaction.  

6 0
3 years ago
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Wewaii [24]
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svetoff [14.1K]
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5 0
3 years ago
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