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wel
3 years ago
7

Dolphins communicate using compression waves (longitudinal waves).  Some of the sounds dolphins make are outside the range of hu

man hearing.
Upon spotting a hungry shark, dolphin A sends a message to dolphin B.  To send this message as effectively as possible, dolphin A would
Physics
2 answers:
White raven [17]3 years ago
8 0
The dolphin would send an underwater message because the water is denser than air and therefore the sound would be louder and would travel faster. The denser the object the faster the sound travels.
11Alexandr11 [23.1K]3 years ago
8 0

Explanation:

Sound is a longitudinal wave. Sound wave consists of compression and rarefaction. It needs a medium to travel. It can travel in solid, liquid and gas. It travels faster in solid in comparison to liquid.

Dolphins communicate with each other using higher frequencies which are outside the range of human hearing.

In the given problem Dolphin A sends a message to dolphin B. Sound will travel through the water. Dolphin A sends a message to dolphin B underwater. A denser medium produces a louder sound.

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Example 4.6 provides a nice example of the overlap between kinematics and dynamics. It is known that the plane accelerates from
kodGreya [7K]

Answer:

ax = 2.60m/s^{2}, t = 26.92s

Explanation:

The acceleration of the plane can be determined by means of the kinematic equation that correspond to a Uniformly Accelerated Rectilinear Motion.

(vx)f^{2} = (vx)i^{2} + 2ax \Lambda x (1)

Where (vx)f^{2} is the final velocity, (vx)i^{2} is the initial velocity, ax is the acceleration and  \Lambda x is the distance traveled.

Equation (1) can be rewritten in terms of ax:

(vx)f^{2} - (vx)i^{2} = 2ax \Lambda x

2ax \Lambda x = (vx)f^{2} - (vx)i^{2}

ax = \frac{(vx)f^{2} - (vx)i^{2}}{2 \Lambda x}  (2)

Since the plane starts from rest, its initial velocity will be zero ((vx) = 0):

Replacing the values given in equation 2, it is gotten:

ax = \frac{(70m/s)^{2} - (0m/s)^{2}}{2(940m)}

ax = \frac{4900m/s}{2(940m)}

ax = \frac{4900m/s}{1880m}

ax = 2.60m/s^{2}

So, The acceleration of the plane is 2.60m/s^{2}    

Now that the acceleration is known, the next equation can be used to find out the time:

(vx)f = (vx)i + axt (3)

Rewritten equation (3) in terms of t:

t = \frac{(vx)f - (vx)i}{ax}

t = \frac{70m/s - 0m/s}{2.60m/s^{2}}

t = 26.92s

<u>Hence, the plane takes 26.92 seconds to reach its take-off speed.</u>

5 0
3 years ago
Here are some energy resources. List the renewable energy resources.
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Solar wind geothermal
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3 years ago
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A Foucault pendulum consists of a brass sphere with a diameter of 32.0 cm suspended from a steel cable 10.0 m long (both measure
Sergio039 [100]

Answer:

T = 44.35 °C

Explanation:

d = 32cm

R = 16 cm

Lsteel = 10m

T1 = 20° C

Space = 0.3cm

The space between the sphere and the floor is represented by δL(total) after the temperature increases.

As the temperature increases, both will expand.

So,

0.3 x 10^(-2) = δL(steel) + δR(brass)

= {L(o) x α(steel) x δT} + {R(o) x {α(brass) x δT}

= {10 x 1.2 x 10^(-5) x (T-20)} + {0.16 x 2 x 10^(-5) x (T-20)}

= 12.32 x 10^(-5) x(T-20)

Therefore (T-20) = (0.3 x 10^(-2)) / {12.32 x 10^(-5)}

T = 20 + 24. 35 = 44.35 °C

8 0
2 years ago
In some countries liquid nitrogen is used on dairy trucks instead of mechanical refrigerators. A 3 hour delivery trip requires .
tensa zangetsu [6.8K]

Answer:

Amount of necessary heat transfer, q = 66.1\times 10^{6} J  

Given:

Volume of liquid Nitrogen, V = 0.200 m^{3}

Density of liquid Nitrogen,  \rho = 808 kg/m^{3}

Temperature, T = - 195.8^{\circ}C

Temperature Rise, T' =  4.0^{\circ}C

Latent heat of Vaporization, L_{v} = 201 kJ/kg

Specific heat capacity of gas, C_{gas} = 1040 J/kg^{\circ}C

Solution:

Now, calculation of heat transfer required to evaporate liquid nitrogen and raise its temperature is given by:

q = mC_{gas}\Delta T + mL_{v}                        (1)

Now, mass, m can be given by:

m = \rho V = 808\times 0.200 = 161.6 kg

Now, from eqn (1):

q = m(C_{gas}\Delta T + L_{v})  

q = 161.6(1040(T' - T) + 201\times 10^{3})  

q = 161.6(1040(4 - (- 195.8)) + 201\times 10^{3})  

q = 66.1\times 10^{6} J

6 0
2 years ago
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