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Aleksandr [31]
3 years ago
6

A baseball is thrown vertically up to a height of 30 m on Earth. If the same ball is thrown up on the moon with the same initial

speed, how much farther will it travel up
Physics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

hmax = 181.48m

Explanation:

In order to calculate the maximum height reached by the same ball in the moon, you first calculate the initial velocity of the ball by using the information about the maximum height on the Earth. You use the following formula:

h_{max}=\frac{v_o^2}{2g}     (1)

hmax: maximum height reached by the ball in the Earth = 30m

vo: initial velocity of the ball = ?

g: gravitational acceleration on Earth = 9.8m/s^2

From the equation (1) you solve for vo:

v_o=\sqrt{2gh_{max}}=\sqrt{2(9.8m/s^2)(30m)}=24.24\frac{m}{s}

Next, you use the same equation (1) but for the gravitational acceleration of the moon, which is given by:

g' = 1.62m/s^2

h_{max}=\frac{(24.24m/s)^2}{2(1.62m/s^2)}=181.48m

The same ball, with the same initial velocity, will reache a heigth of 181m in the moon.

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Alchen [17]
<h2>Answer: x=125m, y=48.308m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which we have two components: x-component and y-component. Being their main equations to find the position as follows:

x-component:

x=V_{o}cos\theta t   (1)

Where:

V_{o}=54.5m/s is the projectile's initial speed

\theta=35\° is the angle

t=2.80s is the time since the projectile is launched until it strikes the target

x  is the final horizontal position of the projectile (the value we want to find)

y-component:

y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}   (2)

Where:

y_{o}=0  is the initial height of the projectile (we are told it  was launched at ground level)

y  is the final height of the projectile (the value we want to find)

g=9.8m/s^{2}  is the acceleration due gravity

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For y (2):

y=0+(54.5m/s)sin(35\°)(2.8s)-\frac{(9.8m/s^{2})(2.8s)^{2}}{2}   (5)

y=48.308m   (6)  This is the vertical final position of the projectile

4 0
3 years ago
A horizontal force, F, acts on a crate weighing 8 N, which moves on a horizontal floor at constant speed. The coefficient of fri
RoseWind [281]

The answer is 24 J

F K =.25*8 N

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A 4.0-kg object has 72 J of kinetic energy.<br> Determine its speed.
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Answer:

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Explanation:

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Where:

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A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy.
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According to the first law of thermodynamics, 
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Minus sign indicates that work is done by the system. 
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