The theoretical yield of I2 in the reaction would be 0.23 g
<h3>Theoretical yield</h3>
This refers to the stoichiometric yield of a reaction.
From the equation of the reaction:
Ca(IO3)2 + 10 KI + 12 HCl → 6 I2 + CaCl2 + 10 KCl + 6 H2O
The mole ratio of Ca(IO3)2 and I2 is 1: 6
Mole of 15.00 mL, 0.0100 M Ca(IO3)2 = 15/1000 x 0.0100
= 0.00015 mole
Equivalent mole of I2 = 0.00015 x 6
= 0.009 mole
mass of 0.0009 I2 = 0.0009 x 253.809
= 0.23 g
More on stoichiometric calculations can be found here: brainly.com/question/6907332
Answer:
K > 1.
Explanation:
∵ The equilibrium constant K = [products]/[reactants].
Since, [products] > [reactants].
<em>∴ The equilibrium constant K > 1.</em>
Since the atomic mass consists of protons and neutrons, that would be the answer.
Answer: <span>C. the atomic mass </span>
Answer:
2.25 M <========= I do not see this in your selection of answers !
Explanation:
Mole weight of Li F
( from periodic table ) = 6.94 + 18.998 = 25.938 gm/mole
56 gm / ( 25.938 gm /mole) = 2.15899 moles
2.15899 mole / (.959) L = 2.25 M
Answer:
electronic configuration: 1s^2,2s^2,2p^3
name: nitrogen
unpaired electron: 3
Explanation:
