Answer:
In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams
Explanation:
This compound is the lead (IV) phosphate.
Grams that occupy 1 mole, means the molar mass of the compound
Pb = 207.2 .3 = 621.6 g/m
P = 30.97 .4 = 123.88 g/m
O = (16 . 4) . 4 = 256 g/m
621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m
CH and O is the reactants while CO and H2O is the products
Answer:
John Newlands
Explanation:
he established the law of octaves
The given question is incomplete. The complete question is:
A chemist adds 0.85 L of a 0.0050M calcium sulfate to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask. Round your answer to significant digits.
Answer: The mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
moles of
=
Now put all the given values in the formula of molarity, we get
Therefore, the mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g