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Archy [21]
3 years ago
7

4. What are the potential sources of error that might cause disagreement between the activity series' prediction of reactions an

d your observations of reactions
Chemistry
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

1. Not to have enough salt water on the foil

2.not cleaning the foil well to remove interfering materials

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Please help me Answer these, I will give the best answer 15 points
den301095 [7]

Answer:

35. Beaker 36. Stirring Rod 37. Bunsen Burner 38. test tube brush 39. Crucible tongs Number 34 is mortar and pestle

Explanation:

I hope its help and got it right anyway, some science tools and kitchen equipments have similar description that makes it easy.

4 0
3 years ago
Please help with this. Thank you
frozen [14]

Answer:

There are four lava flows which are known as, Pahoehoe lava flow, Aa lava flow, Blocky lava flow, and also Pillow lava flow. For basaltic lava flows 10-15 minutes to be thick enough to walk on, when others can take up to 7 months.

Explanation:

6 0
3 years ago
A solution of copper(II) chloride is added to a solution of sodium sulfide.
jeyben [28]

Answer:

a,morunoxidice

Explanation:

carbon - tranite>plangose ,finite, finite,MARETE

8 0
3 years ago
what is a characteristic of matter that allows it to change to something new? THE CORRECT ANSWER GETS BRAINLIEST!!!!​
kodGreya [7K]

Answer:

a chemical property

Explanation:

8 0
3 years ago
Nuclear decay occurs according to first-order kinetics. What is the half-life of europium-152 if a sample decays from 10.0 g to
djyliett [7]

Answer:

13.5 years

Explanation:

Initial Concentration [Ao] = 10g

Final Concentration [A] = 0.768g

Time t= 50 years

Half life t1/2 = ?

These quantities are related by the following equations;

ln[A] = ln[Ao] - kt ......(i)

t1/2 = ln(2) / k ...........(ii)

where k = rate constant

Inserting the values in eqn (i) and solving for k, we have;

ln(0.768) = ln(10) - k (50)

-0.2640 = 2.3026 - 50k

50k = 2.3026 + 0.2640

k = 2.5666 / 50 = 0.051332

Insert the value of k in eqn (ii);

t1/2 = ln(2) / k

t1/2 = 0.693 / 0.051332 = 13.5 years

4 0
3 years ago
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