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Archy [21]
3 years ago
7

4. What are the potential sources of error that might cause disagreement between the activity series' prediction of reactions an

d your observations of reactions
Chemistry
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

1. Not to have enough salt water on the foil

2.not cleaning the foil well to remove interfering materials

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According to Newton's Second Law of Motion, when an object is acted on by an unbalanced force, how will that object respond?
marissa [1.9K]
Newton's Second Law states:
The acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to the mass of the object.

since the net force and the acceleration ar directly proportional, as the net force increases the acceleration will increase.

hope this helps :)


7 0
3 years ago
I need anyone to answer me.. ​
artcher [175]
A. 2,3
B. 19
C. 28
D. 33
4 0
2 years ago
Based on the diagram below, which would have the most inertia?
jeka94

Answer:

The sphere on the left has the most inertia because it has more mass.

Explanation:

Inertia is a property of matter of a substance.

According to Newton's first law of motion, a body continues to stay in the state of rest or constant velocity unless acted upon a external force.

The amount of inertia that an object possess is proportional to the mass of the object.

The sphere on the left is of 300 kg and that on the right is of 30 kg.

Clearly, the sphere on the left has more mass.

Therefore, the sphere on the left has the most inertia.

6 0
3 years ago
Read 2 more answers
a blank in the speed of the molecules allows the attractions between atoms and a little closer together
anygoal [31]
Idk it’s there’s a picture(it won’t load or no picture) but when molecules move slow and are kidna packed together it is a solid
6 0
3 years ago
Write an equilibrium expression for each chemical equation involving one or more solid or liquid reactants or products.
Alex_Xolod [135]

Answer:

a.

Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}

b.

Keq=[O_2]^3

c.

Keq=\frac{[H_3O^+][F^-]}{[HF]}

d.

Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}

Explanation:

Hello there!

In this case, for the attached reactions, it turns out possible for us to write the equilibrium expressions by knowing any liquid or solid would be not-included in the equilibrium expression as shown below, with the general form products/reactants:

a.

Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}

b.

Keq=[O_2]^3

c.

Keq=\frac{[H_3O^+][F^-]}{[HF]}

d.

Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}

Regards!

5 0
2 years ago
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