Answer:
24.5 g of NaCl
Explanation:
We begin from the balanced reaction:
3MgCl₂ + 2Na₃PO₄ → 6NaCl + Mg₃(PO₄)₂
If the sodium phosphate is in excess, then the limting reagent is the magnessium chloride.
We convert mass to moles:
20 g . 1mol / 95.2g = 0.210 moles.
3 moles of MgCl₂ can produce 6 moles of NaCl
0.210 moles of salt, may produce (0.210 . 6) /3 = 0.420 moles
Ratio of reactant is twice the product
We convert the moles to mass:
0.420 mol . 58.45 g/mol = 24.5 g
Answer:
d.have a mass of 1 amu..
Explanation:
Does not match a as the answer for a is electrons B.electron circle around the nucleus because neutrons are inside the nucleus.C.proton and neutrons make the nucleus so the only answer left is .d .which is correct
Explanation:
Sodium metal reacts rapidly with water to form a colourless basic solution of sodium hydroxide (NaOH) and hydrogen gas (H2). The reaction continues even when the solution becomes basic. The resulting solution is basic because of the dissolved hydroxide.
Answer:
![V_2=12.1L](https://tex.z-dn.net/?f=V_2%3D12.1L)
Explanation:
Hello!
In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:
![\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%20%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:
![T_1=20+273=293K\\\\T_2=-40+273=233K](https://tex.z-dn.net/?f=T_1%3D20%2B273%3D293K%5C%5C%5C%5CT_2%3D-40%2B273%3D233K)
Then, we obtain:
![V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BP_1V_1T_2%7D%7BT_1P_2%7D%5C%5C%5C%5CV_2%3D%5Cfrac%7B0.987atm%2A8.50L%2A233K%7D%7B293K%2A0.550atm%7D%5C%5C%5C%5CV_2%3D12.1L)
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