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frosja888 [35]
1 year ago
14

which ionic bond is stronger: the ionic bond between calcium ions and chloride ions in crystalline calcium chloride , or the ion

ic bond between potassium ions and chloride ions in crystalline ? explain.
Chemistry
1 answer:
monitta1 year ago
4 0

CaCl2 has a stronger ionic bond than KCl because Ca+2 is smaller than K+ in size.

<h3>What is the working of ionic bonds ?</h3>

A stable link formed by the complete transfer of the valence electron is known as an ionic bond. This kind of interaction results in the formation of positive ions, also known as cations, and negative ions, also known as anions.

  • This kind of interaction is exemplified by the ionic bond in sodium chloride, a salt. The sodium valence electron is transferred to the outer electron shell of chloride. Ionic molecules form the basis of ionic compounds.

  • The three types of bonds that frequently develop are covalent bonds between nonmetals, ionic bonds between metals and nonmetals, and metallic connections between metals.

Learn more about Ionic bond here:

brainly.com/question/13526463

#SPJ4

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What would you expect to observe when you add flour to a glass of water?
algol [13]

Answer:

hmmm

Explanation:

hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

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3 years ago
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Why do two oxygen atoms form a double covalent bond?
elena-s [515]

A lone oxygen atom has 6 electrons in its outer shell which is not very stable, whereas as full octet (8 outer shell electrons) is stable. In order to achieve this two oxygen atoms will share 4 electrons, each contributing 2 electrons. Since these electrons exist within the orbitals of both atoms, to oxygen atoms essentially achieve a full octet.

5 0
3 years ago
Help!!!!
evablogger [386]

Answer:

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5 0
2 years ago
Calculate the number of grams of oxygen gas in a 24L container at STP
romanna [79]

There are 34 g of oxygen in the container.

We can use the<em> Ideal Gas Law</em> to solve this problem.

pV = nRT

But n = \frac{m}{M}, so

pV = \frac{m}{M}RT and

m = \frac{pVM}{RT}\\

STP is 0 °C and 1 bar, so

m = \frac{\text{1 bar} \times \text{24 L} \times 32.00 \text{ g}\cdot\text{mol}^{-1}}{\text{0.083 14 } \text{bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1}\times\text{273.15 K} } = \textbf{34 g}\\

7 0
3 years ago
If iodine-131 has a half-life of 8 days, how much of a 64.0 g sample of iodine-131 will remain after 32 day?
Mariulka [41]

Answer:

4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.

Explanation:

Half life (t1/2) = 8 days

Original mass (No) = 64 g

Elapsed time (t) = 32 days

Mass remaining (Nt) = ?

Using the half life equation we can obtain the mass remaining (Nt)

Nt = No (1/2) ^t/t1/2

Substituting the values, we have;

Nt = 64 * ( 1/2 ) ^32/8

Nt = 64 * (1/2) ^4

Nt = 64 * 0.0625

Nt = 4 g

So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.

8 0
3 years ago
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