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Zarrin [17]
3 years ago
12

A permanent alteration in the DNA sequence that makes up a gene is called am

Chemistry
2 answers:
vodka [1.7K]3 years ago
7 0
Would definitely be a mutation
Alexxx [7]3 years ago
6 0

Answer:

Gene mutation

Explanation:

A gene mutation is a permanent alteration in the DNA sequence that makes up a gene, such that the sequence differs from what is found in most people. Mutations range in size; they can affect anywhere from a single DNA building block base pair to a large segment of a chromosome that includes multiple genes

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Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
3 years ago
Heat is a form of energy transfer from a _____________________ _______________________ location to a_____________________ ______
Lesechka [4]

Answer:

hotter location to a colder location

4 0
3 years ago
Read 2 more answers
Help have no idea what to do
Irina-Kira [14]
Number one is true !!!!!!????!???????????!!!!!!!!!!!!
8 0
3 years ago
Atomic Structure and Theory [6A.S]:Question 6
-Dominant- [34]

We need to find mass number

\\ \sf\longmapsto Mass\:Number=No\:of\:protons+No\:of\:Neutrons

\\ \sf\longmapsto Mass\:Number=19+21=40

Your answer is 40u

3 0
3 years ago
Read 2 more answers
What is the boiling point of water at an elevation of 1.55×104 ft ?
horsena [70]
The computation for this problem is:
(1.55x10^4 / 1.0x10^3) x 19.8 mm Hg
= 15.5 x 19.88 mm Hg
= 308.14 mm Hg decrease 
= 308.14 x 0.05 C = 15.407 deg C 
deduct this amount to 100
100 – 15.407 = 84.593 C 
ANSWER: 85 deg C (rounded to 2 significant figures)
4 0
3 years ago
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