Answer: V2 = 35.54L
Explanation:
Applying
P1= 67.4, V1= 85, T1= 245, P2= 179.6, V2= ?,. T2=273
P1V1/ T1= P2V2/T2
Substitute and simplify
(67.4*85)/245 = (179.6*V2)/273
V2= 35.54L
Answer: 2Liters
Explanation:
The expression used will be :
where,
= concentration of first antifreeze= 60%
= concentration of second antifreeze= 10%
= volume of first antifreeze = x L
= volume of second antifreeze = 8 L
= concentration of final antifreeze solution= 20%
= volume of final antifreeze = (x+8) L
Now put all the given values in the above law, we get the volume of antifreeze added
Therefore, the volume of 60% antifreeze solution that must be added is 2L
Answer:
Explanation:
Regardless of the type of gas, 1 mole at standard temperature and pressure (STP) occupies a volume of 22.4 liters. In this case the gas is helium (He).
We can set up a ratio.
Multiply by the given number of moles.
The moles of helium will cancel.
Multiply.
5.25 moles of helium gas at STP is 117.6 liters of helium.
Answer:
Both have the same amount of particles.
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ particles.
This implies that 1 mole of Hydrogen contains 6.02×10²³ particles. Also, 1 mole of oxygen contains 6.02×10²³ particles.
Thus, 1 mole of Hydrogen and 1 mole of oxygen contains the same number of particles.
Answer:
The purpose of this guide is to help you write a clear and concise report that summarizes the lab I just completed. This lab showed me how water carries rocks to a new location. For instance how the first model showed how a stream would act with light drizzle to downpour as I saw the outcomes were all if not completely then partially different
I read the information that was given to me before I started each lab lesson and went on from there.
Explanation:
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