Answer:
2.387 mol/L
Explanation:
The reaction that takes place is:
- 2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O
First we <u>calculate how many moles of each reagent were added</u>:
- HCl ⇒ 200.0 mL * 3.85 M = 203.85 mmol HCl
- Ba(OH)₂ ⇒ 100.0 mL * 4.6 M = 460 mmol Ba(OH)₂
460 mmol of Ba(OH)₂ would react completely with (2*460) 920 mmol of HCl. There are not as many mmoles of HCl so Ba(OH)₂ will remain in excess.
Now we <u>calculate how many moles of Ba(OH)₂ reacted</u>, by c<em>onverting the total number of HCl moles to Ba(OH)₂ moles</em>:
- 203.85 mmol HCl *
= 101.925 mmol Ba(OH)₂
This means the remaining Ba(OH)₂ is:
- 460 mmol - 101.925 mmol = 358.075 mmoles Ba(OH)₂
There are two OH⁻ moles per Ba(OH)₂ mol:
- OH⁻ moles = 2 * 358.075 = 716.15 mmol OH⁻
Finally we <u>divide the number of OH⁻ moles by the </u><u><em>total</em></u><u> volume</u> (100 mL + 200 mL):
- 716.15 mmol OH⁻ / 300.0 mL = 2.387 M
So the answer is 2.387 mol/L
When you are converting grams to moles, the operation that you will be doing is dividing by the molar mass to obtain the amount of moles of the given sample.
Einstein's theory of special relativity sets of the speed of light, 186,000 miles per second (300 million meters per second). ... The speed of light in a vacuum is 186,282 miles per second (299,792 kilometers per second), and in theory nothing can travel faster than light.
Hey there!
Consider 100 g of solution:
Mass of NaCl = 3.50% of mass of seawater
( 3.50 / 100 ) * 100 => 3.50 g
Number of moles as shown below:
Molar mass NaCl = 58.44 g/mol
n = Mass / molar mass
n = 3.50 / 58.44 => 0.059 moles of NaCl
Mass of sweater:
Mass of solution - Mass of NaCl
100 - 3.50 = 96.5 g
96.5 g in Kg :
96.5 / 1000 => 0.0965 Kg
Therefore ,calculate molality by using the following formula:
molality = number of moles of solute / mass of solution
molality = 0.059 / 0.0965
molality = 0.61 m
Hope That helps!