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taurus [48]
3 years ago
12

Need helped for this

Chemistry
1 answer:
yarga [219]3 years ago
3 0
Molar mass of PH3: 34.0 g/mol
17.0g PH3 x 1 mol PH3 / 34.0 g = 0.5 mol PH3
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I did this on accident lol
k0ka [10]
Hey what is ur question
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A 44.0 g sample of an unknown metal at 99.0 oC was placed in a constant-pressure calorimeter of negligible heat capacity contain
tatiyna

Answer:

C_m=0.474\frac{J}{g\°C}

Explanation:

Hello.

In this case, since this is a system in which the water is heated up and the metal is cooled down in a calorimeter which is not affected by the heat lose-gain process, we can infer that the heat lost by the metal is gained be water, it means that we can write:

Q_m=-Q_w

Thus, in terms of masses, specific heats and temperatures we can write:

m_mC_m(T_{eq}-T_m)=-m_wC_w(T_{eq}-T_w)

Whereas the equilibrium temperature is the given final temperature of 28.4 °C and we can compute the specific heat of the metal as shown below:

C_m=\frac{-m_wC_w(T_{eq}-T_w)}{m_m(T_{eq}-T_m)}

Plugging the values in and since the density of water is 1.00 g/mL so the mass is 80.0g, we obtain:

C_m=\frac{-80.0g*4.184\frac{J}{g\°C} (28.4\°C-24.0\°C)}{44.0g(28.4\°C-99.0\°C)}\\\\C_m=0.474\frac{J}{g\°C}

Best regards!

6 0
3 years ago
How many grams of KBr are contained in 150. mL of a 0.154 M solution of potassium bromide?
Lostsunrise [7]

Answer:

I think it is B

Explanation:

because the others don't look right

6 0
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How much of a 10 M solution is needed to make 1 liter of all solution?
SashulF [63]

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b is the answer 1000ml

please mark me brainlist

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The symbol is U and its atomic number is 92
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