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natta225 [31]
3 years ago
13

How many moles of aluminum oxide (Al2O3) can be produced from 12.8 moles of oxygen gas (02)

Chemistry
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

Theoretical Yield

Percent yield

Example stoichiometry problem

How much oxygen can be prepared from 12.25 g KClO3 . (Use molar mass KClO3 = 122.5 g.)

Most stoichiometry problems can be solved using the following steps.

Step 1.

Write and balance the equation for the decomposition of KClO3 with heat (∆). 2KClO3 + ∆ → 2KCl + 3O2

Step 2.

Convert what you have (in this case g KClO3) to moles.

# moles = grams/molar mass = 12.25 g /122.5 = 0.100 mole KClO3.

Step 3.

Using the coefficients in the balanced equation, convert moles of what you have (moles KClO3) to moles of what you want (in this case moles oxygen).

0.100 mol KClO3 x (3 moles O2/2 moles KClO3) = 0.100 x (3/2) = 0.150 mole O2.

Step 4.

Convert moles from step 3 to grams.

moles x molar mass = grams

0.150 mole O2 x (32.0 g O2/mole O2) = 4.80 g O2 produced from 12.25 g KClO3. This is the theoretical yield. If the ACTUAL yield is 4.20 grams, calculate percent yield. Percent yield = (actual yield/theoretical yield) x 100 = (4.20/4.80) x 100 = 87.5% yield

NOTE: In step 1, moles can be obtained other ways; in step 4 moles can be converted to other units.

a. For solutions, M x L = moles (or mL x M = millimoles).

b. For gases, L/22.4 = moles

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What happens when nitrogen and hydrogen comes in contact at high temperature and pressure in presence of iron powder and molybde
Sidana [21]

Answer:

<h2>Ammonia Gas</h2>

Explanation:

It result in formation of ammonia gas.

N2 + 3H2 ---<u>iron</u><u>/</u><u>molybdenum</u><u>/</u><u>high</u><u> </u>temp/pres--- > 2 NH3

It forms ammonia gas.

Please mark branliest if you are satisfied with the answer. Thanking in anticipation.

6 0
3 years ago
How many molecules are there in 2.30g of NH3
Vinil7 [7]

Answer:

8.13x10^22 molecules

Explanation:

We can use the Avogadro's number(6.022 x 10^23 units / mole)

2.30 g NH3 (1 mol / 17.03 g ) (6.022 x 10^23 molecules / 1 mol ) = 8.13x10^22 molecules

Hope this helps! Feel free to ask any questions!

6 0
3 years ago
How many moles of Oxygen atoms are contained in 45.9 mol CO2?
Vaselesa [24]

Answer:

Explanation:

10 moles of oxygen atoms.\ \textbf{b)} 91.8 moles of oxygen at

7 0
2 years ago
1. Imagine you have a sealed 20.0 L balloon filled with helium gas at 750 mmHg in the
SVETLANKA909090 [29]

Answer:

17.6510 L

Explanation:

First we should get the number of moles of helium here by Boyle's law

PV=nRT

P=750/760= 0.9868 atm

T=25+273=298 kelvin

R= 0.08206

V= 20L

so

n=PV/RT

n=0.9868×20/0.08206×298

n=0.80707 mol

Then use the same law

V=0.80707×0.08206×263/0.9869=

17.6510L

SO THE VOLUME WILL BE 17.6510 L

6 0
2 years ago
What is the molality of a solution that contains 5 moles of solute in 100 kilograms of water?
slega [8]
<span>Answer:
molality = (moles of solute) / (kilogram of solvent)

moles of solute = (75.2 g AgClO4) / (mole mass AgClO4)
moles of solute = (75.2 g AgClO4) / (207.3206 g/mol)
moles of solute = 0.3627232 mol

molality = (0.3627232 mol) / (0.0752 Kg)
molality = 4.8234468 m or 4.82 m rounded to three significant figures </span>
3 0
3 years ago
Read 2 more answers
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