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horrorfan [7]
3 years ago
11

Estimate the distance (in cm) between the central bright region and the third dark fringe on a screen 5.00 m from two double sli

ts 0.500 mm apart illuminated by 500-nm light.
Physics
1 answer:
Artist 52 [7]3 years ago
5 0

Answer:

y = 1.75 cm

Explanation:

In the double-slit experiment the equation for destructive interference is

           d sin tea = (m + ½)

λ

let's use trigonometry to find the angle

         tan θ = y / L

as all the experiment does not occur at small angles

          tan θ = sin θ / cos θ = sin θ = y / L

we substitute

        y = (m + 1/2 ) λ  L / d

we calculate

         y = (3 + ½) 500 10⁻⁹ 5.00 / 0.5 10⁻³

         y = 1.75 10⁻² m

         y = 1.75 cm

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nikitadnepr [17]

Answer: λ (wavelength) = 3.3 m →  ΔS = 3.3 m

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Answer:

The ratio of their orbital speeds are 5:4.

Explanation:

Given that,

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The orbital speed of satellite B,

v_{B}=\sqrt{\dfrac{GM_{B}}{R_{B}}}......(I)

We need to calculate the ratio of their orbital speeds

Using equation (I) and (II)

\dfrac{v_{A}}{v_{B}}=\sqrt{\dfrac{\dfrac{GM_{A}}{R_{A}}}{\dfrac{GM_{B}}{R_{B}}}}

Put the value into the formula

\dfrac{v_{A}}{v_{B}}=\sqrt{\dfrac{G\times5m\times7r}{G\times7m\times4r}}

\dfrac{v_{A}}{v_{B}}=\dfrac{5}{4}

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3 years ago
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There are 3 significant figures, if that answers the question.
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