We will find that the effective area that must be used to get the desired power is 3,333.33 m^2
The information we have is:
power needed = 1.00 MW = 1,000,000 watts
Energy of the Sun = 1,000 W/m^2
We know that the system has an efficiency of 30%, then per meter square, the energy converted is:
E = 0.3*1,000 W/m^2 = 300 W/m^2
Now we need to find the area (in meters squared) such that:
A*E = 1,000,000 watts
A*(300 W/m^2) = 1,000,000 watts
A = (1,000,000 watts)/(300 W/m^2) = 3,333.33 m^2
So the effective area that must be used is A = 3,333.33 m^2
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