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3 years ago

What is the SI unit for graviational potential energy

Physics

1 answer:

scZoUnD [109]3 years ago

3 0

Gravitational potential energy is energy.
The unit of energy is the Joule.

1 Joule = 1 kilogram-meter² / sec²

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The primary gases of the atmosphere are _____. nitrogen and carbon dioxide nitrogen, oxygen, and argon nitrogen and oxygen nitro

Paladinen [302]

<span>The primary gases of the atmosphere are _____:
</span>
nitrogen, oxygen, and carbondioxide

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3 years ago

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Calculate the amount of energy transferred when a 40w light bulb is left on for 30 minutes.

Alinara [238K]

Answer:

E=72000J or 72kj

Explanation:

The formula is E=pt you need to convert your t from minutes to seconds before proceeding

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3 years ago

How does the intensity of a sound wave change if the distance from the

Alex17521 [72]

Answer:

The new intensity decreases by a factor of 16.

Explanation:

The intensity of sound wave is given by :

$I=\dfrac{P}{A}$

P is power

A is area

$I=\dfrac{P}{4\pi r^2}$

$I\propto \dfrac{1}{r^2}$ , r is distance from the source

If the distance from the source is increased by a factor of 4, r' = 4r

So,

$I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}$

So, the new intensity decreases by a factor of 16.

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3 years ago

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1515

Talja [164]

Complete Question

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1/5.

Answer:

The angle is

Explanation:

From the question we are told that

The light emerging from second Polaroid is 1/5 the unpolarized

Generally the intensity of light emerging from the first Polaroid is mathematically represented as

$I_1 = \frac{I_o}{ 2 }$

Generally from the Malus law the intensity of light emerging from the second Polaroid is mathematically represented

$I_2 = I_1 cos^2 (\theta )$

=> $cos^2 (\theta ) = \frac{I_2}{I_1 }$

=> $cos (\theta) = \sqrt{ \frac{I_2}{I_1} }$

From the question $I_2 = \frac{I_o}{5}$

$cos (\theta) = \sqrt{ \frac{ \frac{ I_o}{5} }{\frac{I_o}{2} } }$

$cos (\theta) = \sqrt{ \frac{2}{5} }$

=> $\theta = cos ^{-1} [\sqrt{\frac{2}{5}} ]$

=> $\theta = 50.77^o$

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3 years ago

How to convert momentum into speed?

Firdavs [7]

In a collision an object experiences a force for a specific amount of time, which results in a change momentum(the objects mass may ethier speed up or slow down). Impulse will be produced because of force appiled to an object over a period of time.

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3 years ago