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3 years ago

How is energy transfer related to the ozone layer and its temperature?

1 answer:

6 0

Energy is transferred<span> between the earth's surface and the atmosphere via conduction, convection, and radiation. Conduction is the process by which heat</span>energy is<span> transmitted through contact with neighboring molecules. ... During the day, solar radiation heats the ground, which heats the air next to it by conduction.</span>

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Describe quantitatively, in words, the relationship between the mass attached to a vertical spring, and the time it takes for th

velikii [3]

Answer:

Direct relationship.

Explanation:

There is a direct relationship between mass attached to vertical spring and the time period to complete one cycle because when the mass increases, more time is taken by the spring to complete one full cycle and vice versa. When the mass of the spring increases, the length of the spring is also increases so due to more length it takes more time to complete one full cycle as compared to less mass attached to the spring.

6 0

3 years ago

A distorted body image may lead to serious health risks. True False

GarryVolchara [31]

The answer would be true, if you viewed yourself as fat but you were actually skinny you would wanna lose weight right? then you would be like a little skeleton and vice versa... hope it helps ^-^

3 0

3 years ago

A biker can ride at 12 m/s on a level road when there is no wind and at 7.5 m/s on a level road when there is a head wind of 5 m

alexandr402 [8]

Answer:

The answer is " $1.94 \ m^2$ ".

Explanation:

Formula:

$F= \frac{1}{2} \times C_D \times density \times area \times velocity^2\\\\Power (P) = F \times velocity \\\\P = \frac{C_D}{2} \times density \times area \times velocity^3\\$

Given value:

$\ P = 10.25 \ W \\\\\ density = 1.2 \ kg/m^3 \\\\\ velocity= 2.5 \\\\$

$10.25 = \frac{C_D A}{2} \times 1.2 \times 2.5^3\\\\C_D A= \frac{10.25 \times 2 }{1.2 \times 2.5^3}\\\\C_D A = 1.94 m^2\\$

8 0

3 years ago

A parallel plate capacitor has circular plates with diameter D=21.5 cm separated by a distance d=1.75 mm. When a potential diffe

OLga [1]

Answer: $E=2.078\times 10^{-10} J/cm^3$

Explanation:

Given

Diameter(D)=21.5 cm

distance between plate=1.75 mm

and we know capacitance is

$C=\frac{\epsilon _0A}{d}$

and we know charge is

Q=CV

and charge density ( $\sigma [tex])[tex]=\frac{Q}{A}=\frac{\epsilon _0AV}{Ad}=\frac{\epsilon V}{d}$

Electric field(E) $=\frac{\sigma }{\epsilon _0}$

Energy density $=\frac{1}{2}\epsilon _0E^2$

Energy desity $=\frac{4\pi \epsilon _0}{8\pi }\frac{V^2}{d^2}$

Energy desity $=\frac{1}{8\pi \cdot 9\times 10^9}\times \left [ \frac{12\times 10^3}{1.75}\right ]^2$

$E=2.078\times 10^{-10} J/cm^3$

3 0

3 years ago

Under which conditions do both convex and concave mirrors form virtual images? State whether or not each can form a real image.I

natali 33 [55]

Concave mirrors can make a real image.when the object is away from the mirror it is called real image and when the object is closer to the mirror it is called virtual mirror.

8 0

3 years ago

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