How is energy transfer related to the ozone layer and its temperature?

1 answer:

6 0

Energy is transferred<span> between the earth's surface and the atmosphere via conduction, convection, and radiation. Conduction is the process by which heat</span>energy is<span> transmitted through contact with neighboring molecules. ... During the day, solar radiation heats the ground, which heats the air next to it by conduction.</span>

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What is the magnification of an astronomical telescope whose objective lens has a focal length of 71 cm and whose eyepiece has a

Rus_ich [418]

To solve this problem it is necessary to apply the concepts related to optical magnification (is the process of enlarging the apparent size, not physical size, of something.). Specifically the angular magnification of an optical telescope is given by

$M = -\frac{f_o}{f_e}$

Where,

$f_o =$ Focal length of the objective lens in a refractor

$f_e =$ Focal length of the eyepiece

Our values are given as

$f_o =$ 71cm

$f_e =$ 2.1cm

Replacing we have

$M = -\frac{f_o}{f_e}$

$M = -\frac{71}{2.1}$

$M = - 33.81$

Therefore the magnification of this astronomical telescope is -33.81

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3 years ago

A box sits on a table. A short arrow labeled F subscript N points up. A short arrow labeled F subscript g points down. A long ar

Aloiza [94]

Answer:

unbalanced and right

Explanation:

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3 years ago

What do you use to light a laboratory burner

Hunter-Best [27]

A needle valve and collar.

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3 years ago

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A particle with charge 3.20×10−19 c is placed on the x axis in a region where the electric potential due to other charges increa

lys-0071 [83]

Answer:

-5 V

Explanation:

The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value

vb−va

is negative.

We can calculate the potential difference between the two points by using the law of conservation of energy:

$\Delta K+ \Delta U=0\\\Delta K + q\Delta V=0$