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aksik [14]
3 years ago
5

How is a sound wave made by plucking a guitar string?.

Physics
2 answers:
frozen [14]3 years ago
8 0

Answer:

Because of the vibration of the string. since it is vibrating it will make the other air molecules vibrate as well and air vibrating is basically a sound wave.

timurjin [86]3 years ago
8 0

Answer:

A sound wave is produced by a vibrating object

Explanation:

When a guitar string vibrates, it sets surrounding air molecules into motion. The frequency of vibration of these air molecules is the same as that of a guitar string.

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Layla shot a balloon straight up in the air and it is in the air round trip for 6.80 s.
Katena32 [7]

Answer:

24mph

Explanation:

it really depends how high but the average speed for that quick will be atleast 24mph if not try 42mph if it is wrong

5 0
3 years ago
Greg is in a bike race. At mile marker four (out of ten), his speed was measured at 13.5 mph. Which best describes the measured
Ipatiy [6.2K]

his speed/ velocity is 13.5 miles per hour


5 0
3 years ago
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Using simple language, explain how your demonstration shows the effect of distance on electric forces. Use the terms electric ch
Eddi Din [679]

Explanation:

For a charge concentrated nearly at a point, the electric field is directly proportional to the amount of charge; it is inversely proportional to the square of the distance radially away from the centre of the source charge and depends also upon the nature of the medium.

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3 years ago
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The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
puteri [66]

Answer:

t=5.3687\ s  is the time taken by the car to accelerate the desired range of the speed from zero at full power.

Explanation:

Given:

Range of speed during which constant power is supplied to the wheels by the car is 0\ mph\ to\ 70\ mph.

  • Initial velocity of the car, v_i=0\ mph
  • final velocity of the car during the test, v_f=32\ mph=14.3052\ m.s^{-1}
  • Time taken to accelerate form zero to 32 mph at full power, t=1.2\ s
  • initial velocity of the car, u_i=0\ mph
  • final desired velocity of the car, u_f=64\ mph=28.6105\ m.s^{-1}

Now the acceleration of the car:

a=\frac{v_f-v_i}{t}

a=\frac{14.3052-0}{1.2}

a=11.921\ m.s^{-1}

Now using the equation of motion:

u_f=u_i+a.t

64=0+11.921\times t

t=5.3687\ s is the time taken by the car to accelerate the desired range of the speed from zero at full power.

8 0
3 years ago
A wire that is 0.65 m long and carrying a current of 8.2 A is at right angles to a uniform magnetic field. The force on the wire
Luda [366]

Answer:

0.075 T

Explanation:

When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by

F=ILB sin \theta

where

I is the current in the wire

L is the length of the wire

B is the strength of the magnetic field

\theta is the angle between the direction of I and B

In this problem we have:

L = 0.65 m is the length of the wire

I = 8.2 A is the current in the wire

F = 0.40 N is the force experienced by the wire

\theta=90^{\circ} since the current is at right angle with the magnetic field

Solving the formula for B, we find the strength of the magnetic field:

B=\frac{F}{IL sin \theta}=\frac{0.40}{(8.2)(0.65)(sin 90^{\circ})}=0.075 T

3 0
3 years ago
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