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tiny-mole [99]
3 years ago
15

How many nanoseconds does it take light to travel 2.50 feet in a vacuum

Physics
1 answer:
Monica [59]3 years ago
5 0
A handy-dandy "rule of thumb" that I and many other engineers
have been using for years is:       

                                     1 nanosecond ===> 1 foot. 

Let's figure it out and see whether that's even close:

Speed of light in vacuum = 299,792,458 meters per second.

         (299,792,458 m/s) x ( 1 sec / 10⁹ nanosec) x (3.28084 ft/meter)

     =  (299,792,458 x 1 x 3.28084 x 10⁻⁹)  ft/nanosec

     =            0.983571  ft/nanosec  .

       That's  1.64%  less than  1.000000 .
       The engineer's handy-dandy rule of thumb is valid.

2.5 feet would take

           (2.5  x  0.983571 sec)  =   2.45893 nanoseconds
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Rudik [331]

Answer:

Explanation:

Given that,

Weight of jet

W = 2.25 × 10^6 N

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Center of gravity of plane 10.6m behind the front wheel

A. Normal force entered on the ground by front wheel.

Taking moment about the the about the real wheel.

Check attachment for better understanding

So,

Clock wise moment = anti-clockwise moment

W × 5.4 = N × 16

2.25 × 10^6 × 5.4 = 16•N

N = 2.25 × 10^6 × 5.4 / 16

N = 7.594 × 10^5 N

B. Normal force on each of the rear two wheels.

Using the second principle of equilibrium body.

Let the rear wheel normal be Nr and note, the are two real wheels, then, there will be two normal forces

ΣFy = 0

Nr + Nr + N — W = 0

2•Nr = W—N

2•Nr = 2.25 × 10^6 — 7.594 × 10^5

2•Nr = 1.491 × 10^6

Nr = 1.491 × 10^6 / 2

Nr = 7.453 × 10^5 N

6 0
3 years ago
These are nontoxic, nonflammable chemicals containing atoms of carbon, chlorine, and fluorine that have created a hole in the oz
yarga [219]
Hello! The nontoxic, nonflammable chemicals containing atoms of carbon, chlorine, and fluorine that have created a hole in the ozone layer are the Chlorofluorocarbons (CFCs)

These are compounds developed and improved by Thomas Midgley in the late 1920s. They were used as refrigerants and aerosol propellants.

These compounds created a hole in the ozone layer by the following reactions:

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galina1969 [7]

Answer:

0.04225 Nm

Explanation:

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d = Diameter of knob = 1.3 cm

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Force is given by

F=N\mu\\\Rightarrow F=5\times 0.65\\\Rightarrow F=3.25\ N

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\tau_t=F\times r\\\Rightarrow \tau_t=3.25\times 0.0065\\\Rightarrow \tau_t=0.021125\ Nm

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\tau_f=F\times r\\\Rightarrow \tau_f=3.25\times 0.0065\\\Rightarrow \tau_f=0.021125\ Nm

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