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tiny-mole [99]
3 years ago
15

How many nanoseconds does it take light to travel 2.50 feet in a vacuum

Physics
1 answer:
Monica [59]3 years ago
5 0
A handy-dandy "rule of thumb" that I and many other engineers
have been using for years is:       

                                     1 nanosecond ===> 1 foot. 

Let's figure it out and see whether that's even close:

Speed of light in vacuum = 299,792,458 meters per second.

         (299,792,458 m/s) x ( 1 sec / 10⁹ nanosec) x (3.28084 ft/meter)

     =  (299,792,458 x 1 x 3.28084 x 10⁻⁹)  ft/nanosec

     =            0.983571  ft/nanosec  .

       That's  1.64%  less than  1.000000 .
       The engineer's handy-dandy rule of thumb is valid.

2.5 feet would take

           (2.5  x  0.983571 sec)  =   2.45893 nanoseconds
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Answer:

A) The speed of the potato at the lowest point of its motion is 7.004 m/s

B) The tension on the string at this point is 8.5347 N

Explanation:

Here we have that the height from which the potato is allowed to swing  is 2.5 m

Therefore we have ω₂² = ω₁² + 2α(θ₂ - θ₁)

Where:

ω₂ = Final angular velocity

ω₁ = Initial angular velocity = 0 rad/s

α = Angular acceleration

θ₂ = Final angle position

θ₁ = Initial angle position

However, we have potential energy of the potato

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At he bottom of the swing, the potential energy will convert to kinetic energy as follows

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1/2·m·v² = 7.1125 J

Therefore,

v² = 7.1125 J/(1/2×m) = 7.1125 J/(1/2×0.290) = 49.05

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B) Here we have the tension given by

Tension T in the string = weight of potato + Radial force of motion

Weight of potato = mass of potato × gravity

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∴ Tension T in the string = m×g + m×v²/r = 0.290×(9.81 + 7.004²/2.5)

T = 8.5347 N

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