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ss7ja [257]
3 years ago
9

What is the reason there is a belt of asteroids between Mars and Jupiter?

Physics
2 answers:
melamori03 [73]3 years ago
8 0
Its due to Jupiter's huge huge gravitational pull 
madam [21]3 years ago
5 0
We don't know.  It could be material that just couldn't condense
into a planet in that region. 

(In fact, the way the planets are arranged, it turns out that the
average distance from the sun to the center of the asteroid belt
is exactly where we would expect to find a planet.)

If the asteroids are actually material that failed to condense into a
planet, then the huge gravity of Jupiter might have been responsible
for keeping the material disturbed.
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Stable isotopes, radioisotopes, oxygen

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2) What did Rutherford discover in his experiment?<br> a) nucleus<br> b) electrons<br> c) neutrons
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A) nucleus because some aims reflected off the gold foil proving that there was something bigger inside the atom hence discovering the nucleus
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2 years ago
A rock falls from the top of a hill to the bottom. The total energy of the rock at the top isn’t the same as the sum of its pote
mart [117]

Answer:

A) some of the rocks energy is transformed to thermal energy

Explanation:

If we neglect air resistance during the fall of the rock, than the mechanical energy of the rock (which is sum of its potential energy and its kinetic energy) would be constant during the entire motion, so the total energy of the rock at the top would be the same as the sum of its potential energy and kinetic energy at the bottom.

However, this not occurs, due to the presence of air resistance. In fact, air resistance acts against the fall of the rock, and because of the friction between the molecules of air and the surface of the rock, the rock loses part of its energy. This energy is converted into thermal energy of the molecules of the air.

3 0
3 years ago
a car advertisement claims their car can go from a stopped position to move 60 miles per hour in 5 seconds the advertisement is
zysi [14]
What do you want us to anwser
7 0
3 years ago
A long thin uniform rod of length 1.50 m is to be suspended from a frictionless pivot located at some point along the rod so tha
Dvinal [7]

Answer:

0.087 m

Explanation:

Length of the rod, L = 1.5 m

Let the mass of the rod is m and d is the distance between the pivot point and the centre of mass.

time period, T = 3  s

the formula for the time period of the pendulum is given by

T = 2\pi \sqrt{\frac{I}{mgd}}    .... (1)

where, I is the moment of inertia of the rod about the pivot point and g is the acceleration due to gravity.

Moment of inertia of the rod about the centre of mass, Ic = mL²/12

By using the parallel axis theorem, the moment of inertia of the rod about the pivot is

I = Ic + md²

I = \frac{mL^{2}}{12}+ md^{2}

Substituting the values in equation (1)

3 = 2 \pi \sqrt{\frac{\frac{mL^{2}}{12}+ md^{2}}{mgd}}

9=4\pi^{2}\times \left ( \frac{\frac{L^{2}}{12}+d^{2}}{gd} \right )

12d² -26.84 d + 2.25 =  0

d=\frac{26.84\pm \sqrt{26.84^{2}-4\times 12\times 2.25}}{24}

d=\frac{26.84\pm 24.75}{24}

d = 2.15 m , 0.087 m

d cannot be more than L/2, so the value of d is 0.087 m.

Thus, the distance between the pivot and the centre of mass of the rod is 0.087 m.

3 0
3 years ago
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