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2 years ago

What is the reason there is a belt of asteroids between Mars and Jupiter?

Physics

2 answers:

melamori03 [73]2 years ago

8 0

Its due to Jupiter's huge huge gravitational pull

madam [21]2 years ago

5 0

We don't know. It could be material that just couldn't condense
into a planet in that region.

(In fact, the way the planets are arranged, it turns out that the
average distance from the sun to the center of the asteroid belt
is exactly where we would expect to find a planet.)

If the asteroids are actually material that failed to condense into a
planet, then the huge gravity of Jupiter might have been responsible
for keeping the material disturbed.

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James weighs 67 pounds on Earth. He has a mass of 30 kilograms. Which of the following is true?

morpeh [17]

Answer:

I think its B. James would have a smaller mass on the Moon than he does on Earth.

sorry if i did it wrong

4 0

2 years ago

Read 2 more answers

Determine the CM of a rod assuming its linear mass density λ (its mass per unit length) varies linearly from λ = λ0 at the left

Dahasolnce [82]

Answer:

$x_c= \dfrac{5}{9}L$

$I=\dfrac {7}{12}\lambda_ 0 L^3$

Explanation:

Here mass density of rod is varying so we have to use the concept of integration to find mass and location of center of mass.

At any distance x from point A mass density

$\lambda =\lambda_0+ \dfrac{2\lambda _o-\lambda _o}{L}x$

$\lambda =\lambda_0+ \dfrac{\lambda _o}{L}x$

Lets take element mass at distance x

dm =λ dx

mass moment of inertia

$dI=\lambda x^2dx$

So total moment of inertia

$I=\int_{0}^{L}\lambda x^2dx$

By putting the values

$I=\int_{0}^{L}\lambda_ ox+ \dfrac{\lambda _o}{L}x^3 dx$

By integrating above we can find that

$I=\dfrac {7}{12}\lambda_ 0 L^3$

Now to find location of center mass

$x_c = \dfrac{\int xdm}{dm}$

$x_c = \dfrac{\int_{0}^{L} \lambda_ 0(1+\dfrac{x}{L})xdx}{\int_{0}^{L} \lambda_0(1+\dfrac{x}{L})}$

Now by integrating the above

$x_c=\dfrac{\dfrac{L^2}{2}+\dfrac{L^3}{3L}}{L+\dfrac{L^2}{2L}}$

$x_c= \dfrac{5}{9}L$

So mass moment of inertia $I=\dfrac {7}{12}\lambda_ 0 L^3$ and location of center of mass $x_c= \dfrac{5}{9}L$

8 0

2 years ago

What is a fault?

Free_Kalibri [48]

C) A crack in earth's crust where movement occurs. An example of this is the San Andreas Fault.

A) is repulsion
B) continental crust (lighter crust)
D) Hotspot

3 0

2 years ago

Find the acceleration of a car with a mass of 1,200 kg and a force of 11,000 N.<br> Please help

netineya [11]

Answer:

9.17 m/s^2

Explanation:

Formula for force is given by

F = m*a

where F is the force in newton

m is the mass of body in KG

and

a is the acceleration of body on m/s^2

_______________________________________________

Given

F = 11,000

mass = 1,200 Kg

we have to find value of acceleration

using

F = m*a

11,000 = 1200*a

=> a = 11,000 /1200 = 9.17

Thus, the acceleration of a car is 9.17 meter per second square

5 0

2 years ago

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topjm [15]

A deep zone.........................

4 0

2 years ago