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4 years ago

What products form when a hydrocarbon is completely combusted in air?

1 answer:

6 0

<span>The products of the combustion of a hydrocarbon are dependent on if the reaction is run to completion, therefore, you require sufficient Oxygen to completely combust the hydrocarbon. If run to completion the products are H20 and CO2. If not then some CxHy and some O2 are left.</span>

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A mixture of CO2 and Kr weighs 31.7 g and exerts a pressure of 0.665 atm in its container. Since Kr is expensive, you wish to re

elena-s [515]

Answer:

11.94 grams of carbon dioxide were originally present.

19.94 grams of krypton can you recover.

Explanation:

Mass of carbon dioxide gas = x

Mass of krypton gas = y

x + y = 31.7 g

Moles of carbon dioxide gas = $n_1=\frac{x}{44 g/mol}=$

Moles of krypton gas = $n_2=\frac{y}{84 g/mol}=$

Mole fraction of krpton = $\chi '$

Total pressure of the mixture = P = 0.665 atm

Partial pressure of carbon dioxide gas = p

Partial pressure of krypton gas before removal of carbon dioxide gas = p'

Partial pressure of krypton gas after removal of carbon dioxide gas = p'' = 0.309 atm

p' = p'' = 0.309 atm

0.665 atm = p + 0.309 atm

p = 0.665 atm - 0.306 atm = 0.359 atm

Partial pressure of krypton can also be given by :

$p'=P\times \chi '$

$0.309 atm=0.665 atm\times \frac{n_2}{n_1+n_2}$

$0.309 atm=0.665 atm\times \frac{\frac{y}{84}}{\frac{x}{44}+\frac{y}{84}}$

$0.4645=\frac{\frac{y}{84}}{\frac{x}{44}+\frac{y}{84}}$ ..[2]

Solving [1] and [2]:

x = 11.94 g

y = 19.76 g

11.94 grams of carbon dioxide were originally present.

19.94 grams of krypton can you recover.

7 0

4 years ago

With your class, look up the element names for each symbol in the word "BOOK" and list the element names.

aleksandr82 [10.1K]

Explanation:

The word BOOK; is made up of 4 letters and each actually represents the symbol of an element.

An element is a distinct substance that cannot be split-up into simpler substances.

B - Boron

O - Oxygen

K - Potassium

We can see that the word BOOK shows us elements boron, oxygen, oxygen and potassium.

3 0

3 years ago

What is the balanced equation for solid ammonium nitrate (NH4NO3) decomposes explosively to form nitrogen gas, oxygen gas, and w

Karolina [17]

Answer:

2NH4NO3 —> 2N2 + O2 + 4H2O

Explanation:

We begin by writing the skeletal equation as shown below:

NH4NO3 —> N2 + O2 + H2O

The equation can be balance as follow:

There are 4 atoms of H on the left side of the equation and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

NH4NO3 —> N2 + O2 + 2H2O

Now we have a total of 4 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 1/2 in front of O2 as shown below:

NH4NO3 —> N2 + 1/2O2 + 2H2O

Now, multiply through by 2 to clear the fraction as shown below

2NH4NO3 —> 2N2 + O2 + 4H2O

Now the equation is balanced

3 0

3 years ago

1.Beginning with the new moon, place the phases of the moon in order. Identify each phase.

iVinArrow [24]

Answer:

I cant see the picture but

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8 0

3 years ago

Two waves travel through each other, and a crest forms with an amplitude smaller that either original waves. What has happened?

KonstantinChe [14]

Answer:

This is what I think it is, correct me if I'm wrong. Answer is stated below:

Explanation:

Destructive Interference

Two waves combine to form a wave with a smaller amplitude than either the original wave. Destructive interference can occur when the crest of one wave overlaps the trough of another wave. If the crest has a larger amplitude than the trough of the other wave, a part of it remains.

8 0

3 years ago