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geniusboy [140]
3 years ago
12

What is the balanced equation for solid ammonium nitrate (NH4NO3) decomposes explosively to form nitrogen gas, oxygen gas, and w

ater vapor​
Chemistry
1 answer:
Karolina [17]3 years ago
3 0

Answer:

2NH4NO3 —> 2N2 + O2 + 4H2O

Explanation:

We begin by writing the skeletal equation as shown below:

NH4NO3 —> N2 + O2 + H2O

The equation can be balance as follow:

There are 4 atoms of H on the left side of the equation and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

NH4NO3 —> N2 + O2 + 2H2O

Now we have a total of 4 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 1/2 in front of O2 as shown below:

NH4NO3 —> N2 + 1/2O2 + 2H2O

Now, multiply through by 2 to clear the fraction as shown below

2NH4NO3 —> 2N2 + O2 + 4H2O

Now the equation is balanced

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A 25.00 ml solution of sulfuric acid H2SO4 is titrated to phenolphthalein end point with 27.00 ml of 1.700 M KOH
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<h3>Answer:</h3>

0.918 M

<h3>Explanation:</h3>

Assuming the question requires we calculate the Molarity of sulfuric acid:

We are given:

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  • Volume of the base, KOH = 27.00 mL
  • Molarity of the base, KOH is 1.70 M

We can calculate the molarity of the acid using the following steps;

<h3>Step 1: Write the chemical equation for the reaction.</h3>

The reaction is an example of a neutralization reaction where a base reacts with an acid to form salt and water.

Therefore, the balanced equation will be;

H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)

<h3>Step 2: Determine the moles of the base, KOH </h3>

When given molarity and the volume of a solution, the number of moles can be calculated by multiplying molarity with volume.

Number of moles = Molarity × Volume

                             = 1.700 M × 0.027 L

                              = 0.0459 moles

Thus, moles of KOH used is 0.0459 moles

<h3>Step 3: Determine the number of moles of the Acid, H₂SO₄</h3>

From the reaction, 1 mole of the acid reacts with 2 moles of KOH

Therefore, the mole ratio of H₂SO₄ to KOH is 1 : 2

Thus, moles of H₂SO₄ = Moles of KOH ÷ 2

                                     = 0.0459 moles ÷ 2

                                     = 0.02295 moles

<h3>Step 4: Calculate the molarity of the Acid </h3>

Molarity is the concentration of a solution in moles per liter

Molarity = Moles ÷ Volume

Molarity of the acid = 0.02295 moles ÷ 0.025 L

                                = 0.918 M

Thus, the molarity of the acid, H₂SO₄ is 0.918 M

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Since water molecules are polar, they are more attracted to molecules that are also polar.

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