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4 years ago

7. Binary molecular compounds are made of two __________. *

Chemistry

2 answers:

anyanavicka [17]4 years ago

6 0

Answer:

For 7: The correct answer is c.

For 8: The correct answer is d.

Explanation:

For 7:

Binary molecular compounds are defined as the compounds formed from the combination of only two elements. Examples are: $H_2O,SF_6$ etc..

These compounds are formed when two non-metal elements combine together. The first element contains partial positive charge and second element contains partial negative charge.

Hence, the correct option is c.

For 8:

For the naming of binary molecular compounds, we use the prefix to indicate how many of each element is present in the compound.

For 1' we use 'mono', for '2' we use 'di', for '3' we use 'tri', for '4' we use 'tetra', for '5' we use 'penta', for '6' we use 'hexa', for '7' we use 'septa', for '8' we use 'octa', for 9 we use 'nona' and for '10' we use 'deca'.

Hence, the correct option is d.

dybincka [34]4 years ago

6 0

7. C. Is Your Answer.

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2. Using the following data, calculate the average atomic mass of magnesium (give your answer to the nearest

arlik [135]

Answer:

24.32

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Mass of A = 24

Abundance (A%) = 78.70%

Isotope B

Mass of B = 25

Abundance (B%) = 10.13%

Isotope C:

Mass of C = 26

Abundance (C%) = 11.17%

Average atomic mass of Mg =..?

The average atomic mass of Mg can be obtained as illustrated below:

Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

Average atomic mass = [(24 × 78.70)/100] + [(25 × 10.13)/100] + [(26 × 11.17)/100]

= 18.888 + 2.5325 + 2.9042

= 24.3247 ≈ 24.32

Therefore, the average atomic mass of magnesium (Mg) is 24.32

8 0

4 years ago

Which of the following statements is true? A) This reaction will be spontaneous only at high temperatures. B) This reaction will

viktelen [127]

Answer:

D) This reaction will be nonspontaneous only at high temperatures.

Explanation:

According the equation of Gibb's free energy -

∆G = ∆H -T∆S

∆G = is the change in gibb's free energy

∆H = is the change in enthalpy

T = temperature

∆S = is the change in entropy .

And , the sign of the ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

ΔG < 0 , the reaction is Spontaneous

ΔG > 0 , the reaction is non Spontaneous

ΔG = 0 , the reaction is at equilibrium

The reaction has the value for ∆H = negative , and ∆S = negative ,

Now ,

∆G = ∆H -T∆S

= ( - ∆H ) - T( - ∆S )

= ( - ∆H ) +T( ∆S )

Now, for making the reaction Spontaneous ΔG = negative ,

Hence ,

The temperature is low, then the value for ΔG will be negative , i.e. , Spontaneous reaction .

And , vice versa , at higher temperature , the reaction will have ΔG positive , and the reaction will be non -Spontaneous reaction .

The standard free energy of formation will be zero , only for the compounds that are in their pure form ,

Hence , Al(s) will have ΔG = 0 .

7 0

3 years ago

A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base

tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ = 0.00375 mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

$HN_3 + OH- ---> N^-_{3} + H_2O$

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction = 0.025 + 0.0133 = 0.0383 L

Concentration of $HN_3$ = $\dfrac{0.001755}{0.0383}$ = 0.0458 M

Concentration of $N^{-}_3$ = $\dfrac{ 0.001995 }{0.0383}$ = 0.0521 M

GIven that :

Ka = $1.9 x 10^{-5}$

Thus; it's pKa = 4.72

$pH =4.72 + log(\dfrac{ \ 0.0521}{0.0458})$

$pH =4.72 + log(1.1376)$

$pH =4.72 + 0.05598$

$pH =4.77598$

pH ≅ 4.80

3 0

3 years ago

The dimensions of a cupboard are 1.31 m wide

Mnenie [13.5K]

Answer:

The volume of cupboard is 2.0043 m³.

Explanation:

Given data:

width of cupboard = 1.31 m

length of cupboard = 0.9 m

height of cupboard = 1.70 m

Volume = ?

Solution:

Volume = length × width × height

Volume = 0.9 m × 1.31 m × 1.70 m

Volume = 2.0043 m³

The volume of cupboard is 2.0043 m³.

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3 years ago

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Nina [5.8K]

<span>One atom of silicon can properly be combined in a compound with two atoms of oxygen.</span>

7 0

3 years ago

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