Answer:
a=2.304×10¹⁶m/s²
Explanation:
Given data
Distance d=2.5 nm=2,5×10⁻⁹m
Mass of proton m=1.6×10⁻²⁷kg
charge of proton q=1.6×10⁻¹⁹C
To find
acceleration a
Solution
Apply the Coulombs Law
Where k is coulombs constant (k=9×10⁹Nm²/C²)
q=q₁=q₂
r=d
So
Answer:
17.7 cm^3
Explanation:
depth, h = 120 m
density of water, d = 1000 kg/m^3
V1 = 1.4 cm^3
P1 = P0 + h x d x g
P2 = P0
where, P0 be the atmospheric pressure
Let V2 be the volume of the bubble at the surface of water.
P0 = 1.01 x 10^5 Pa
P1 = 1.01 x 10^5 + 120 x 1000 x 9.8 = 12.77 x 10^5 Pa
Use
P1 x V1 = P2 x V2
12.77 x 10^5 x 1.4 = 1.01 x 10^5 x V2
V2 = 17.7 cm^3
Thus, the volume of bubble at the surface of water is 17.7 cm^3.
To solve this question, all you have to do is set up a proportion with the information known and the information unknown and solve for the final variable, after setting them equal to each other.
2 mm/25 = ?/1
2/25 = 8/100 = 0.08 mm
1 page of the textbook would be 8 hundredths of a mm.
The answer is c step-up voltage have lower number of turns
Answer:
0.0443 m/s
Explanation:
= Mass of honeybee = 0.15 g
= Mass of popsicle stick = 4.75 g
= Velocity of honeybee
= Velocity of stick = 0.14 cm/s
In this system the linear momentum is conserved
The velocity of the bee is 4.43 cm/s or 0.0443 m/s
