All categories

3 years ago

A 1500 kg car accelerats from 55.0 m/s to 90.0 m/s. Calculate the impulse experienced by the car

Physics

1 answer:

ioda3 years ago

7 0

Answer:

The impulse experienced by the car is 52,500 kg.m/s.

Explanation:

Given;

mass of the car, m = 1500 kg

initial velocity of the car, u = 55 m/s

final velocity of the car, v = 90 m/s

The impulse experienced by the car is the change in linear momentum, calculated as follows;

J = ΔP = mv - mu

ΔP = m(v - u)

ΔP = 1500(90 - 55)

ΔP = 52,500 kg.m/s

Therefore, the impulse experienced by the car is 52,500 kg.m/s.

You might be interested in

What is kinematics?<br>explain!!~<br><br>thankyou ~

artcher [175]

Answer:

Kinematics is the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

-the features or properties of motion in an object.

Explanation:

Hope this helps <3

Have a great day!

7 0

2 years ago

Read 2 more answers

WILL MARK BRAINLIST!!! only for correct answer<br> NEED CORRECT ANSWER ASAPPP

Nataly [62]

Answer:

number 4

Explanation:

The reflection of light happens when the light bounces off the reflecting surface. That is described by the last (bottom) schematics.

Therefore, select answer number 4.

5 0

3 years ago

Which diagram best represents the electric field around a negatively charged conducting sphere? (See pic)

dalvyx [7]

The answer is D !!!!!!!

3 0

3 years ago

A balanced relationship between the energy that you intake and your bodys energy output is the definition of _____.

Jet001 [13]

Whole body METABOLISM

5 0

3 years ago

Consider one such cell where the magnitude of the potential difference is 65 mV, and the inner surface of the membrane is at a h

Gelneren [198K]

Answer: W = $1.04.10^{-20}$ J

Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.

The work to transport an ion from a lower potential side to a higher potential side is calculated by

$W=q.\Delta V$

q is charge;

ΔV is the potential difference;

Potassium ion has +1 charge, which means:

p = $1.6.10^{-19}$ C

To determine work in joules, potential has to be in Volts, so:

$\Delta V=65.10^{-3}V$

Then, work is

$W=1.6.10^{-19}.65.10^{-3}$

$W=1.04.10^{-20}$

To move a potassium ion from the exterior to the interior of the cell, it is required $W=1.04.10^{-20}$ J of energy.

8 0

3 years ago

A 1500 kg car accelerats from 55.0 m/s to 90.0 m/s. Calculate the impulse experienced by the car​

A 1500 kg car accelerats from 55.0 m/s to 90.0 m/s. Calculate the impulse experienced by the car