A 1.10-kg wrench is acting on a nut trying to turn it. The length of the wrench lies directly to the east of the nut. A force 15

Question

2 years ago

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A 1.10-kg wrench is acting on a nut trying to turn it. The length of the wrench lies directly to the east of the nut. A force 15

0.0 N acts on the wrench at a position 15.0 cm from the center of the nut in a direction 30.0° north of east. What is the magnitude of the torque about the center of the nut?

Physics

1 answer:

Reika [66] · Answer 1 · 2022-04-13T16:32:55+03:00

Reika [66]2 years ago

3 0

This can be solved with the following procedure:
<span>150N * sin30 *. 15 = 11.25NM.
</span>Remember to u<span>se the triangle method for visualization, draw the right triangle with the properties given. Hope this is useful</span>