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kirill115 [55]
3 years ago
13

A 1.10-kg wrench is acting on a nut trying to turn it. The length of the wrench lies directly to the east of the nut. A force 15

0.0 N acts on the wrench at a position 15.0 cm from the center of the nut in a direction 30.0° north of east. What is the magnitude of the torque about the center of the nut?
Physics
1 answer:
Reika [66]3 years ago
3 0
This can be solved with the following procedure:
<span>150N * sin30 *. 15  = 11.25NM.
</span>Remember to u<span>se the triangle method for visualization, draw the right triangle with the properties given. Hope this is useful</span>
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