Answer:
The deer traveled 1300m + 500m + 300m, for a total distance. The exact same motion, distance and displacement have significantly different values. It tells you the rate at which an object's displacement, or position, changes.
Answer:
0.78m/s
Explanation:
Now the momentum ensued by the boy throwing the package Is
Mass of package × velocity of package =4.5×13=58.5m/s
This momentum initiated a momentum on the boy-boat system
Total mass of the boy-boat system is 24+53=75kg
Let the velocity ensued by the boat be v.
Hence from conservation of momentum
58.5 =75×v
v= 58.5/75= 0.78m/s
Answer:
if there is only one planet in the universe and the ball is there it will have 0 kinetic energy if the ball is in the very center of that planet only if the planet itself is absolutely motionless. its at its highest if the planet is moving away from the ball at a slightly faster speed forever. Between point A and B both potential energy and kinetic energy are at perfect 0.
Explanation:
never will have a measurable kinetic or potential energy status unless every single object is included in the calculation.
At t =0, the velocity of A is greater than the velocity of B.
We are told in the question that the spacecrafts fly parallel to each other and that for the both spacecrafts, the velocities are described as follows;
A: vA (t) = ť^2 – 5t + 20
B: vB (t) = t^2+ 3t + 10
Given that t = 0 in both cases;
vA (0) = 0^2 – 5(0) + 20
vA = 20 m/s
For vB
vB (0) = 0^2+ 3(0) + 10
vB = 10 m/s
We can see that at t =0, the velocity of A is greater than the velocity of B.
Learn more: brainly.com/question/24857760
Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. Spacecrafts A and B are flying parallel to each other through space and are next to each other at time t= 0. For the interval 0 <t< 6 s, spacecraft A's velocity v A and spacecraft B's velocity vB as functions of t are given by the equations va (t) = ť^2 – 5t + 20 and VB (t) = t^2+ 3t + 10, respectively, where both velocities are in units of meters per second. At t = 6 s, the spacecrafts both turn off their engines and travel at a constant speed. (a) At t = 0, is the speed of spacecraft A greater than, less than, or equal to the speed of spacecraft B?
