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3 years ago

There are no current plans for returning to the moon. True False

Physics

2 answers:

inysia [295]3 years ago

8 0

True that’s my answer

Otrada [13]3 years ago

3 0

True because as of right now NASA is putting more money for budgeting in 2020 an estimated 1.6 million so they can have a mission to moon possible in 2024.

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Two resistors, of R1 = 3.11 Ω and R2 = 6.15 Ω, are connected in series to a battery with an EMF of 24.0 V and negligible interna

Firlakuza [10]

Part (a):
1- Since the resistors are in series, therefore, the total resistance is the summation of the two resistors.
Therefore:
Rtotal = R1 + R2 = 3.11 + 6.15 = 9.26 ohm

2- Since the two resistors are in series, therefore, the current flowing in both is the same. We will use ohm's law to get the current as follows:
V = I*R
V is the voltage of the battery = 24 v
I is the current we want to get
R is the total resistance = 9.26 ohm
Therefore:
24 = 9.26*I
I = 24 / 9.26
I = 2.59 ampere

Part (b):
To get the voltage across the second resistor, we will again use Ohm's law as follows:
V = I*R
V is the voltage we want to get
I is the current in the second resistor = 2.59 ampere
R is the value of the second resistor = 6.15 ohm
Therefore:
V = I*R
V = 2.59 * 6.15
V = 15.9285 volts

Hope this helps :)

7 0

3 years ago

900n pushes a wedge 0.10 m into a log, if the work done on the log is 50j what is the efficiency of the wedge

mariarad [96]

Answer:

100

Explanation:

mark me brainliest

7 0

3 years ago

3. In the wave models, you imagined adding energy into the wave by

castortr0y [4]

Answer:

by moving your hands up and down your we're creating transverse wave which travel in a right angle shape towards your friend

7 0

3 years ago

A. What is the frequency of blue light that has a wavelength of 450 nm?

erastova [34]

Answer

a)Given,

Wavelength of blue light = 450 n m = 450 x 10⁻⁹ m

Speed of light = 3 x 10⁸ m/s

we know,

$c = \nu \lambda$

$\nu = \dfrac{c}{\lambda}$

$\nu = \dfrac{3\times 10^8}{450\times 10^{-9}}$

$\nu = 6.67 \times 10^{14}\ Hz$

b)Given,

Wavelength of red light = 650 n m = 650 x 10⁻⁹ m

Speed of light = 3 x 10⁸ m/s

we know,

$c = \nu \lambda$

$\nu = \dfrac{c}{\lambda}$

$\nu = \dfrac{3\times 10^8}{650\times 10^{-9}}$

$\nu = 4.62 \times 10^{14}\ Hz$

3 0

3 years ago

A high voltage transmission line with a resistance of 0.51 Ω/km carries a current of 1099 A. The line is at a potential of 1300

Illusion [34]

<h2>Answer:</h2>

$\boxed{P=96.09MW}$

<h2>Explanation:</h2>

First of all, we need to figure out what is the resistance in that line. In this problem, the total resistance is not given directly, but we can calculate it because we know it in terms of 0.51 Ω/km and since the distance from the power station to the city is 156km, then:

$R_{line}=0.51 \frac{\Omega}{km}.156km \\ \\ R_{line}=79.56\Omega$

So we can calculate the power loss as:

$P=I^2R \\ \\ Where: \\ \\I=1099A \\ \\ P=(1099)^2(79.56) \\ \\ P=96092647.56W \\ \\ Remember \ that \ 1MW=10^6W \ So: \\ \\ P=96092647.56W(\frac{1M}{10^6}) \\ \\ \boxed{P=96.09MW}$

Finally, the power loss due to resistance in the line is 96.09MW

5 0

3 years ago