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pychu [463]
3 years ago
12

What happens to the magnitude of the force of gravitation between two objects if: 1. distance between the objects is tripled? 2.

mass of both objects doubled? 3. mass of both objects as well as the distance distance between them is doubled? EES CLASS TEACHER GRADE 9 A Oct 5 3 class comments
Physics
2 answers:
Ludmilka [50]3 years ago
8 0
<span>2. mass of both objects doubled? 
Hope it helped!</span>
VashaNatasha [74]3 years ago
3 0
2. mass of both objects doubled, because with two negatives makes a positive in resulting of my answer....(this formula i made up, i use it on problems like this, i feel so accomplished)
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Describe what happens to water waves when they strike a flat surface?
shutvik [7]

Answer:

In this case reflection occurs.

Explanation:

This happens when they bounce on objects that they can not pass through.

Hope it helps

okay.

6 0
3 years ago
Calculate the unit cell edge length for an 79 wt% Ag- 21 wt% Pd alloy. All of the palladium is in solid solution, and the crysta
ankoles [38]

Answer:

The edge length is 0.4036 nm

Solution:

As per the question:

Density of Ag, \rho = 10.49 g/cm^{3}

Density of Pd, \rho = 12.02 g/cm^{3}

Atomic weight of Ag, A = 107.87 g/mol

Atomic weight of Pd, A' = 106.4 g/mol

Now,

The average density, \rho_{a} = \frac{n A_{avg}} {V_{c}\times N_{A}}

where

V_{c} = a^{3}  = Volume of crystal lattice

a = edge length

n = 4 = no. of atoms in FCC

Therefore,

\rho_{a} = = \frac{n A_{avg}} {V_{c}\times N_{A}}

Therefore, the length of the unit cell is given as:

a = (\frac{nA_{avg}}{\rho_{a}\times N_{a}})^{1/3}            (1)

Average atomic weight is given as:

A_{avg} = \frac{100}{\frac{C_{Ag}}{A_{Ag}} + \frac{C_{Pd}}{A_{Pd}}}

where

C_{Ag} = 79 %

A_{Ag} = 107

C_{Pd} = 21%

A_{Pd} = 106

Therefore,

A_{avg} = \frac{100}{\frac{79}{107} + \frac{21}{106}} = 106.78

In the similar way, average density is given as:

\rho_{a} = \frac{100}{\frac{C_{Ag}}{\rho_{Ag}} + \frac{C_{Pd}}{\rho_{Pd}}}

\rho_{a} = \frac{100}{\frac{79}{10.49} + \frac{21}{12.02}} = 10.78 g/cm^{3}

Therefore, edge length is given by eqn (1) as:

a = (\frac{4\times 106.78}{10.78\times 6.023 X 10^23})^{1/3} = 4.036\times 10^{- 8} cm = 0.4036\times 10^{- 9} m = 0.4036 nm

5 0
3 years ago
1. If you add air to a flat tire through a single small entry hole, why does the air spread out to fill the tire?
ikadub [295]

Answer:

The tire fills up just like anything else that holds air when u pump a ball or tire up it fills all the way up cause it is a small confined space and after filling it with air the atoms of the air fill the tire up

Explanation:

7 0
3 years ago
Which statement best describes an atom? (2 points)
alekssr [168]

Answer:

A group of protons and neutrons that are surrounded by electrons  I think that's the answer...

Explanation:

7 0
3 years ago
Read 2 more answers
A material that can be hit without shattering is?<br> viscous, flammable, hard, malleable
nika2105 [10]
Malleable

Malleability is a property of matter, that’s specializes in metals, in which these metals can be bended, twisted or formed into a thinner sheets, and not being able to shatter to pieces instead it can be formed into a new shape. Unlike the other three, take for instance hardness. If a hard object such as wood for example when used with an axe it breaks and it is lead to smithereens. Flammable like is when applied to fire can dramatically explode when hit it obviously breaks.



3 0
3 years ago
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