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pychu [463]
4 years ago
12

What happens to the magnitude of the force of gravitation between two objects if: 1. distance between the objects is tripled? 2.

mass of both objects doubled? 3. mass of both objects as well as the distance distance between them is doubled? EES CLASS TEACHER GRADE 9 A Oct 5 3 class comments
Physics
2 answers:
Ludmilka [50]4 years ago
8 0
<span>2. mass of both objects doubled? 
Hope it helped!</span>
VashaNatasha [74]4 years ago
3 0
2. mass of both objects doubled, because with two negatives makes a positive in resulting of my answer....(this formula i made up, i use it on problems like this, i feel so accomplished)
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Answer:

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Explanation:

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What is the weight on Earth of a girl with a mass of 32 kg (F = ma)?
GenaCL600 [577]

Answer:

F = 313.6 N

Explanation:

weight is the force acting on an object due to gravity.

so,

  • f = ma (m = mass, a = acceleration)
  • f = 32 × 9.8
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( note : i have taken acceleration due to gravity as 9.8, it can be taken as an approx of 10, so if you have to take 10, the weight of girl will be 320 Newton )

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em>

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3 years ago
Mass is measured in ____________, and weight is measured in ______________.
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MASS is measured in KILOGRAMS

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A ball with a mass of 3kg is dropped from the top of a building this is 20m high. what is the velocity of the ball when it is 10
anzhelika [568]

Answer:

Velocity=14[m/s]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy.

In the attached image we can see the illustration of the ball falling from the height of 20 meters, at this time the potential energy will have the following value.

Ep=m*g*h\\where:\\m=3[kg]\\h=20[m]\\

Ep=3*9.81*20\\Ep=588.6[J]

When the ball passes through half of the distance (10m) its potential energy will have decreased by half as shown below.

Ep=3*9.81*10\\Ep=294.3[m]

If we know that potential energy is transformed into kinetic energy, we can find the value of speed.

Ek=\frac{1}{2} *m*v^{2} \\therefore\\v=\sqrt{\frac{Ek*2}{m} } \\v=\sqrt{\frac{294.3*2}{3} } \\\\v=14[m/s]

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4 years ago
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