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podryga [215]
3 years ago
5

A student needs 7.6 liters of a 0.18 molar solution for an experiment. How many grams of solute does the student need if the mol

ar mass of the solute is 22.71 g/mol? Round your answer to the nearest 0.01
Chemistry
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

31.07 g

Explanation:

First we <u>calculate how many moles of solute would there be in 7.6 liters of a 0.18 molar solution</u>, using the <em>definition of molarity</em>:

  • molarity = moles / volume
  • 0.18 M = moles / 7.6 L
  • moles = 1.368 mol

Now <u>we calculate the mass of 1.368 moles of solute</u>, using the <em>given molar mass</em>:

  • 1.368 mol * 22.71 g/mol = 31.07 g

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jarptica [38.1K]

Answer:

6.95 x 10²³ molecules/particles

Explanation:

First we need to find the total Empirical Mass. We can find this by adding each element's mass together.

Al = 26.982,

O = 15.999

H = 1.008

26.982 + 3(15.999) + 3(1.008) = 78.003.

Now we divide by the mass given (90 grams).

90/78.003 = 1.153801777.

We then take that number and multiply it by avogadro's number (6.022 x 10²³)

1.153801777 x avogadro's number = 6.95 x 10²³

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If we require 2Al2O3

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M = 22.1 g
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