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podryga [215]
3 years ago
5

A student needs 7.6 liters of a 0.18 molar solution for an experiment. How many grams of solute does the student need if the mol

ar mass of the solute is 22.71 g/mol? Round your answer to the nearest 0.01
Chemistry
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

31.07 g

Explanation:

First we <u>calculate how many moles of solute would there be in 7.6 liters of a 0.18 molar solution</u>, using the <em>definition of molarity</em>:

  • molarity = moles / volume
  • 0.18 M = moles / 7.6 L
  • moles = 1.368 mol

Now <u>we calculate the mass of 1.368 moles of solute</u>, using the <em>given molar mass</em>:

  • 1.368 mol * 22.71 g/mol = 31.07 g

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Explanation:

This is correct!

Ions that exist in both the reactant and product side of the equation are referred to as spectator ions. Overall, they do not partake in the reaction. If they are present on both sides of the equation, you can cancel them out.

An example is;

Na+(aq) + Cl​−​​(aq) + Ag​+(aq) + NO​3​−​​(aq) → Na​+​​(aq) + NO​3​−​​(aq) + AgCl(s)

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Answer:

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Answer:

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Explanation:

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