The correct matches are as follows:
<span>1.instantaneous combustion
</span>G.burning<span>
2.mass of substances before and after a reaction is the same
</span>C.Law of Conservation of Matter<span>
3.substances that combine
</span>A.reactants
<span>
4. Yields or makes
</span>B.arrow symbol
<span>
5.rapid oxidation
</span>F.explosion<span>
6.new substance
</span>D.product
<span>
7.slow oxidation
</span>E.rust
<span>
Hope this answers the question. Have a nice day.
</span>
We first calculate the energy contained in one photon of this light using Planck's equation:
E = hc/λ
E = 6.63 x 10⁻³⁴ x 3 x 10⁸ / 590 x 10⁻⁹
E = 3.37 x 10⁻²² kJ/photon
Now, one mole of atoms will excite one mole of photons. This means that 6.02 x 10²³ photons will be excited
(3.37 x 10⁻²² kJ/photon) x (6.02 x 10²³ photons / mol)
The energy released will be 202.87 kJ/mol
Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s
Explanation :
The integrated rate law equation for second order reaction follows:
![k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%5Cleft%20%28%5Cfrac%7B1%7D%7B%5BA%5D%7D-%5Cfrac%7B1%7D%7B%5BA%5D_o%7D%5Cright%29)
where,
k = rate constant = 
t = time taken = ?
[A] = concentration of substance after time 't' = 0.180 mol/L
![[A]_o](https://tex.z-dn.net/?f=%5BA%5D_o)
= Initial concentration = 0.360 mol/L
Putting values in above equation, we get:
Hence, it take time for the concentration to become 0.180 mol/L will be, 277.8 s
Atoms are the unit of the molecule of the compound. The 3.01 x 10²⁴ atoms of oxygen are present in 5 moles of water and 3 moles of carbon dioxide in the sample.
<h3>What are atoms?</h3>
Atoms are the smallest fundamental unit of the compounds that can be given by Avogadro's number.
For calculating the oxygen atoms in 5 mole water:
If 1 mole = 6.02 × 10²³
Then, 5 moles = 5 × 6.02 × 10²³
Hence, 3.01 x 10²⁴ atoms of oxygen are present in 5 moles of water.
Moles of carbon dioxide in the sample is calculated as:
If 1 mole of carbon dioxide = 6.02 × 10²³ molecules
Then moles in 1.8 x 10²⁴ molecules will be,
(1.8 x 10²⁴ molecules) ÷ (6.02 × 10²³ molecules) = 3 moles
Hence, 3 moles of carbon dioxide is present in the sample.
Learn more about Avogadro's number here:
brainly.com/question/5098076
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