Answer
let the oxidation of sulphur is x
2(+1)+x+4(-2)=0
+2+x-8=0
+2-8+x=0
-6+x=0
x=6
Explanation:
i hope this will help you:)
Pressure of the gas P1 = 30.7 kpa
When it doubled P2 = 61.4 kpa
Temperature T1 = 0 => T1 =. 0 + 273 =273
Temperature T2 =?
We have pressure temperature equation P1T1 = P2T2
=> T2 = P1T1 / P2 = (30.7 x 273) / 61.4 = 136.5
So the temperature for doubling the pressure is 136.5.
Answer:
The balloon will occupy a volume of 6.48 L
Explanation:
<u>Step 1: </u>Data given
internal pressure = 1.00 atm
volume = 4.50 L
Temperature = 20.0 °C
<u>Step 2:</u> Calculate new volume via the ideal gas law
P*V = n*R*T
(P1*V1)/ T1 = (P2*V2)/T2
⇒ with P1 = 1.00 atm
⇒ with V1 = 4.50 L
⇒ with T1 = 20.0 °C = 293 Kelvin
⇒ with P2 = 0.600 atm
⇒ with V2 = TO BE DETERMINED
⇒ with T2 = -20°C = 253 Kelvin
(1.00atm * 4.50 L)/293 Kelvin = (0.600 atm*V2) / 253 Kelvin
0.01536 = 0.00237 V2
V2 = 6.48 L
The balloon will occupy a volume of 6.48 L
Answer:
the chemical change occur in burning paper.
boiling water does not make any chemical change
melting gold "
dissolving sugar in water "
in these examples the reactant remains as the same , even if you melt gold it is gold itself, it only change its state.
The answer is Prokaryotic
