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Marizza181 [45]
3 years ago
14

How can sulfur acid be both a result and a cause?

"absmiddle" class="latex-formula">
Chemistry
1 answer:
Rom4ik [11]3 years ago
5 0
Health effects of sulphur<span>. All living things need </span>sulphur. It is especially important for humans<span> because it is part of the amino acid methionine, which is an absolute dietary requirement for us. ... Elemental </span>sulphur<span> is not </span>toxic<span>, but many simple </span>sulphur <span>derivates are, such as </span>sulphur<span> dioxide (SO</span>2<span>) and hydrogen sulfide.</span>
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3 years ago
Describe the range of the radii of most atoms
andriy [413]
The radii of most atoms are actually measured in the Ǻ, or Angstrom. We can do it in nanometers too, however. 
<span>First, we take the radius of the smallest atom, He (Helium). Atomic radius = .031 nm. The largest atom, stable atom is Fr (Francium), with atomic radius = .27 nm. </span>
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8 0
4 years ago
Natural selection is defined as_____ a. the changes that occur in a population that do not affect survival. b. the changes in th
Dmitry_Shevchenko [17]

Answer:

The answer is B, natural selection is the process whereby <u>organisms better adapted to their environment tend to survive and produce more offspring</u>. The theory of its action was first fully expounded by Charles Darwin and is now believed to be the main process that brings about <u>evolution</u>.

5 0
4 years ago
KOH + HBr - KBr + H2O<br> Which is the acid in this reaction?
Reptile [31]

Answer:

HBr is a strong acid

Explanation:

KBr is a salt which makes a base . also KOH is a base

7 0
3 years ago
Read 2 more answers
A chemist makes 940. mL of sodium carbonate (Na_2CO_3) working solution by adding distilled water to 200. mL of a 0.171 m stock
Alexxandr [17]

Answer:

The answer is 0.0698 M

Explanation:

The concentration was prepared by a serial dilution method.

The formula for the preparation I M1V1 = M2V2

M1= the concentration of the stock solution = 0.171 M

V1= volume of the stock solution taken = 200 mL

M2 = the concentration produced

V2 = the volume of the solution produced = 940 mL

Substitute these values in the formula

0.171 × 200 = 490 × M2

34.2 = 490 × M2

Make M2 the subject of the formula

M2 = 34.2/490

M2 = 0.069795

M2 = 0.0698 M ( 3 s.f)

The concentration of the Chemist's working solution to 3 significant figures is 0.0698M

6 0
3 years ago
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