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Ber [7]
3 years ago
10

How many moles are in 83.1g of CaBr2​

Chemistry
1 answer:
9966 [12]3 years ago
8 0

Answer:

0.416 mol CaBr₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

83.1 g CaBr₂

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar mass of Br - 79.90 g/mol

Molar Mass of CaBr₂ - 40.08 + 2(79.90) = 199.88 g/mol

<u>Step 3: Convert</u>

<u />83.1 \ g \ CaBr_2(\frac{1 \ mol \ CaBr_2}{199.88 \ g \ CaBr_2} ) = 0.415749 mol CaBr₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.415749 mol CaBr₂ ≈ 0.416 mol CaBr₂

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