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andrew-mc [135]
1 year ago
15

Calculate how many half-lives are required for a number of radio-active nuclei to decrease to one-millionth of

Physics
2 answers:
Alex73 [517]1 year ago
6 0

Answer:

it would depend on which element u would be considering

Explanation:

as helium , oxygen , carbon ,sodium and other would be easier while plutonium , americium and other very radioactive elements would be harder

Naya [18.7K]1 year ago
4 0

Answer:

~ 20 half lives

Explanation:

(1/2) ^n   = 1/1,000,000     n = number of half-lives

                                        LOG both sides to get

n LOG 1/2 = -6

n = -6/(LOG (1/2)) = 19.931    or approx  20 half lives

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Ilia_Sergeevich [38]
Momentum of car

Given: Mass m= 1,400 Kg;    V = 6.0 m/s

Formula:  P = mv    

                P = (1,400 Kg)(6.0 m/s)

                P = 8,400 Kg.m/s

Velocity of the rider to have the same momentum as a car.

Mass of rider and bicycle  m = 100 Kg

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V = P/m

V = 8,400 Kg.m/s/100 Kg

V = 84 m/s









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A car is accelerating at 30 m/s2, if the car is 400 kg how much force
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(1 point) A projectile is fired from ground level with an initial speed of 600 m/sec and an angle of elevation of 30 degrees. Us
konstantin123 [22]

Answer:

(a) The range of the projectile is 31,813.18 m

(b) The maximum height of the projectile is 4,591.84 m

(c) The speed with which the projectile hits the ground is 670.82 m/s.

Explanation:

Given;

initial speed of the projectile, u = 600 m/s

angle of projection, θ = 30⁰

acceleration due to gravity, g = 9.8 m/s²

(a) The range of the projectile in meters;

R = \frac{u^2sin \ 2\theta}{g} \\\\R = \frac{600^2 sin(2\times 30^0)}{9.8} \\\\R = \frac{600^2 sin (60^0)}{9.8} \\\\R = 31,813.18 \ m

(b) The maximum height of the projectile in meters;

H = \frac{u^2 sin^2\theta}{2g} \\\\H = \frac{600^2 (sin \ 30)^2}{2\times 9.8} \\\\H = \frac{600^2 (0.5)^2}{19.6} \\\\H = 4,591.84 \ m

(c) The speed with which the projectile hits the ground is;

v^2 = u^2 + 2gh\\\\v^2 = 600^2 + (2 \times 9.8)(4,591.84)\\\\v^2 = 360,000 + 90,000.064\\\\v = \sqrt{450,000.064} \\\\v = 670.82 \ m/s

5 0
2 years ago
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