Answer: The continuation and the last part of the question is (3) Determine the expression for E0 by substitution of r0 into the above equation for EN. What is the equation that represents the expression for E0?
Explanation:
The detailed steps and appropriate derivation and by differentiation is shown in the attachment.
The knowledge of differential calculus is applied.
Answer:
12500W
Explanation:
Given parameters:
Work done = 250000J
Time taken = 20s
Unknown:
Power of the crane = ?
Solution:
Power is the defined as the rate at which work is being done;
Mathematically;
Power =
insert the parameters and solve;
Power =
= 12500W
Answer:
a = 8.06 m/s²
Explanation:
The acceleration of this car can be found using the first equation of motion:

where,
a = acceleration = ?
vf = final speed = 26.8 m/s
vi = initial speed = 0 m/s
t = time = 3.323 s
Therefore,

<u>a = 8.06 m/s²</u>
Answer:
0.280 s
Explanation:
I set it up as 5.22=(55)(0.0266)/x and then solved for x to be 2.80.
Answer:
9] V = D ÷ T
Take any distance value from the graph and its relevant time.
V = 4 ÷ 2
V = 2 m/s
[You will notice that any distance values with its time will give you 2 m/s as its speed. This means that speed is constant throughout.]
10] Take the distance value and its time for the highest peak of B.
V = 20 ÷ 2
V = 10 m/s