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atroni [7]
3 years ago
9

HELP ASAP Describe when contact metamorphism occurs?

Physics
2 answers:
iVinArrow [24]3 years ago
6 0

Answer:

Contact metamorphism occurs adjacent to igneous intrusions and results from high temperatures associated with the igneous intrusion. Since only a small area surrounding the intrusion is heated by the magma, metamorphism is restricted to the zone surrounding the intrusion, called a metamorphic or contact aureole.

Explanation:

diamong [38]3 years ago
5 0

Contact metamorphism occurs adjacent to igneous intrusions and results from high temperatures associated with the igneous intrusion. Since only a small area surrounding the intrusion is heated by the magma, metamorphism is restricted to the zone surrounding the intrusion, called a metamorphic or contact aureole

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does a Neon atom emits specific frequencies of light that correspond to decreases in energy of its electrons.
zlopas [31]

Answer:

Yes, the frequency of light emitted is a property of the difference between the levels of energy of its electrons.

Explanation:

Neon atom is a noble gas which glows when its electrons de-excites after absorbing energy.

Niels Bohr postulated that the energy level in all atoms are quantized, thus electrons do not exist in-between two levels.  When electrons in the Neon atom are excited, this increase in energy causes them to jump to a higher energy levels. On de-excitation, the electrons drops to their initial level releasing the absorbed energy in the form of a photon.

The photon emitted has a frequency that is directly proportional to the energy change in the electron.

6 0
3 years ago
A 6 kg mass collides with a body at rest .After collision they travel together with a velocity equal
Mars2501 [29]

Answer:

12 kg

Explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

After the collision, they have the same velocity, so v₁ = v₂ = v:

m₁ u₁ + m₂ u₂ = m₁ v + m₂ v

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

We know that m₁ = 6 kg, u₂ = 0 m/s, and v = u₁ / 3.

(6 kg) u₁ + m₂ (0 m/s) = (6 kg + m₂) (u₁ / 3)

(6 kg) u₁ = (6 kg + m₂) (u₁ / 3)

6 kg = (6 kg + m₂) (1/3)

18 kg = 6 kg + m₂

m₂ = 12 kg

3 0
4 years ago
Hiii please help i’ll give brainliest if you give a correct answer please thanks!
ryzh [129]

Answer:

i Guess 1 or 3

Explanation:

yea 1 or 3 or just  guess hard

7 0
3 years ago
Who first thought that the sun orbited the earth?
TEA [102]

Answer:

It's Ptolemy

Explanation:

He thought the Earth was the universe's center and everything revolved around us.

4 0
3 years ago
How far (in feet) could a pitcher throw a baseball on flat, level ground if he can throw it at 100mph? (Neglect wind drag and th
ehidna [41]

Answer:

R = 668.19 ft  

Explanation:

given,

speed of the ball thrown by the pitcher = 100 mph

to travel maximum distance θ = 45°

distance traveled by the ball = ?

using formula

1 mph = 0.44704 m/s

100 mph = 44.704 m/s

R = \dfrac{u^2sin2\theta}{g}

R = \dfrac{44.704^2sin2\times 45}{9.81}

R = 203.71 m

1 m  = 3.28 ft

R = 203.71 × 3.28

R = 668.19 ft  

hence, ball will go at a distance of 668.19 ft   when pitcher throw it at 100 mph.

6 0
3 years ago
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