Answer: 2.13 × 10^-4 A
Explanation:
Given that the RLC circuit has a resistance R = 200 Ω and an inductance L = 15 mH.
Its oscillation frequency F = 7000 Hz
The initial current I = 25 mA = 25/1000 or 25 × 10^-3 A
Since there is no charge on the capacitor, the current after complete 5 circle will be achieved by using the formula in the attached file.
Please find the attached file for the remaining explanation for the solution.
The rod's mass moment of inertia is 5kgm².
<h3>Moment of Inertia:</h3>The "sum of the product of mass" of each particle with the "square of its distance from the axis of rotation" is the formula for the moment of inertia.
The Parallel axis Theorem can be used to compute the moment of inertia about the end of the rod directly or to derive it from the center of mass expression. I = kg m². We can use the equation for I of a cylinder around its end if the thickness is not insignificant.
If we look at the rod we can assume that it is uniform. Therefore the linear density will remain constant and we have;
or = M / L = dm / dl
dm = (M / L) dl
Here the variable of the integration is the length (dl). The limits have changed from M to the required fraction of L.
Mass of the rod = 15 kg
Length of the rod = 2.0 m
Moment of Inertia, I =
= 5 kgm²
Therefore, the moment of inertia is 5kgm².
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