Answer:
Monosaccharide
Explanation:
Apples contain high levels of fructose, which is a monosaccharide.
Answer : The pH of buffer is 9.06.
Explanation : Given,
Concentration of HBrO = 0.34 M
Concentration of KBrO = 0.89 M
Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[KBrO]}{[HBrO]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BKBrO%5D%7D%7B%5BHBrO%5D%7D)
Now put all the given values in this expression, we get:
Therefore, the pH of buffer is 9.06.
Atomic mass W = 183.84 u.m.a
183.84 g ----------- 6.02x10²⁴ atoms
?? g ---------------- 2.1x10²⁴ atoms
2.1x10²⁴ x 183.84 / 6.02x10²⁴ =
3.860x10²⁶ / 6.02x10²⁴ = 641.30 g
hope this helps!
Answer:
23.9g of Fe₂O₃ are produced
Explanation:
<em>Are formed when 16.7g of Fe reacts completely...</em>
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Based on the reaction:
4Fe + O₃ → 2Fe₂O₃
<em>4 moles of Iron react per 1 mole of O₃ producing 2 moles of Fe₂O₃.</em>
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To solve this question we need to convert the mass of iron to moles. The ratio of reaction is 2:1 -That is, 2 moles of Fe produce 1 mole of Fe₂O₃-. Thus, we can find the moles of Fe₂O₃ produced and its mass:
<em>Moles Fe -Molar mass: 55.845g/mol-:</em>
16.7g Fe * (1mol / 55.845g) = 0.299 moles of Fe
<em>Moles Fe₂O₃:</em>
0.299 moles Fe * (2 mol Fe₂O₃ / 4 mol Fe) = 0.150 moles Fe₂O₃
<em>Mass Fe₂O₃ -Molar mass 159.69g/mol-:</em>
0.150 moles Fe₂O₃ * (159.69g / mol) =
<h3>23.9g of Fe₂O₃ are produced</h3>
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